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7nadin3 [17]
3 years ago
6

The first stage of a space vehicle consumed fuel and oxidizer at the rate of 1.75 x 104 kg/s, with an exhaust speed of 2.40 x 10

3 m/s. Find the acceleration (in m/s2) of the vehicle just as it lifted off the launch pad on the Earth, if the vehicle's initial mass was 3.00 x 106 kg. (Note: You must include the force of gravity to solve the problem.)
Physics
1 answer:
Molodets [167]3 years ago
3 0

Answer:

a=4.19 m/s^{2}

Explanation:

In order to solve this problem, we must first draw a free body diagram of the situation. (See attached picture)

from this diagram, we can do the following sum of forces:

\sum F=ma

where m is the mass of the rocket and a is its acceleration.

F_{e}-mg=ma

where F_{e} is the force of exhaust. We can solve this for the acceleration, so we get:

a=\frac{F_{e}-mg}{m}

we can find the force of exhaust by using the momentum formula:

Ft=mv

so we can solve this for the force:

F_{e}=\frac{mv}{t}

the problem already tells us what m/t is equal to, so we can directly substitute:

F_{e}=(1.75x10^{4}kg/s)(2.40x10^3m/s)

which yields:

F_{e}=42x10^6 N

So we can now substitute:

a=\frac{42x10^6N-(3x10^6kg)(9.81m/s^{2})}{3x10^6kg}

so:

a=4.19 m/s^{2}

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With 51 gallons of fuel in its tank, the airplane has a weight of 2390.7 pounds. What is the weight of the plane with 81 gallons
Shtirlitz [24]

Answer: 2561.7 pounds

Explanation:

If we assume the total weight of an airplane (in pounds units) as a <u>linear function</u> of the amount of fuel in its tank (in gallons) and we make a Weight vs amount of fuel graph, which resulting slope is 5.7, we can use the slope equation of the line:

m=\frac{Y-Y_{1}}{X-X_{1}}  (1)

Where:

m=5.7 is the slope of the line

Y_{1}=2390.7pounds is the airplane weight with  51 gallons of fuel in its tank (assuming we chose the Y axis for the airplane weight in the graph)

X_{1}=51gallons is the fuel in airplane's tank for a total weigth of 2390.7 pounds (assuming we chose the X axis for the a,ount of fuel in the tank in the graph)

This means we already have one point of the graph, which coordinate is:

(X_{1},Y_{1})=(51,2390.7)

Rewritting (1):

Y=m(X-X_{1})+Y_{1}  (2)

As Y is a function of X:

Y=f_{(X)}=m(X-X_{1})+Y_{1}  (3)

Substituting the known values:

f_{(X)}=5.7(X-51)+2390.7  (4)

f_{(X)}=5.7X-290.7+2390.7  (5)

f_{(X)}=5.7X+2100  (6)

Now, evaluating this function when X=81 (talking about the 81 gallons of fuel in the tank):

f_{(81)}=5.7(81)+2100  (7)

f_{(81)}=2561.7  (8)   This means the weight of the plane when it has 81 gallons of fuel in its tank is 2561.7 pounds.

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Answer:

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