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3 years ago

What is the area of a rectangle that has a width of 4 miles and a length of 15 miles ?

Mathematics

2 answers:

kiruha [24]3 years ago

8 0

Answer:

60mi² Hope this helped :)

Step-by-step explanation:

Airida [17]3 years ago

8 0

Answer:

60 miles squared

Step-by-step explanation:

l x w is the formula for area of a square/rectangle

4 x 15 = 60

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Which ordered pair is a solution of the equation y= -5x +4......(2,14) (5, -29) (3, -19) (5, -21)

Ratling [72]

1) 2x+4y=10
3x+5y=14 .

find d2, dx2, and dy

2) Solve the system of equations algebraically and show your work.

2x + 3y = 12
2x - y = 4

3) Which of the ordered pairs (5,5),(5,0) and (-3,2) can be found in the shaded solution area for the system of inequalities below? (The ordered pair must be in the double shaded region or it is not a solution of the system.)

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3 years ago

Determine the equation of the circle graphed below.

sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

Find the centre of the circle.

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

$Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})$

$=(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)$

Find the radius of the circle.

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

$Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}$

$=\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6$

Therefore,

$Radius ,r = \frac{6}{2} = 3$

Standard equation of a circle:

$(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.$

Therefore , equation of the circle ;

$(x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9$

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