The width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.
<u>Explanation:</u>
Given:
Two rectangles are proportional.
Length and width of 1 rectangle = 6 : 8
Dimensions of the other rectangle = ?
Let length and width of the other rectangle be x : y
According to the question:


So, the width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.
Answer:
c
Step-by-step explanation:
So first I would say, what if all of them were dimes, how far away would it be from $14?
So 92 coins * 10 cents = $9.20
So it's 4.80 dollars away from 14 dollars.
So if we were to switch one to a quarter, it would increase by 0.15 cents.
So we want to see how many increases we need to reach 4.80 dollars more.
4.80/0.15 = 32
So there are 32 quarters and 60 dimes.
If I understand the question correctly, you can have the same amount of change be two different percentages by having 4 quarters and 100 pennies.
Each quarter is 25%
Each penny is 1%
(am i explaining this right)