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2 years ago

How many different ways can an after school club of 13 students line up?

Mathematics

2 answers:

Bas_tet [7]2 years ago

6 0

Answer:

13 x 13 = 169 different ways

maksim [4K]2 years ago

3 0

Answer:

13! or 6227020800

Step-by-step explanation:

With no restrictions, we can figure out the answer to be 13! by the following analysis:

For the first position in line, there are 13 different students who could fill that spot. If we fill it and proceed to the next position in line, there are now only 12 students left who can fill it, since one is already in line. Then the next position only has 11 possibilities, and the next 10, and so on.

Multiplying all of this together gives us 13*12*11*10*9*8*7*6*5*4*3*2*1 or 13!

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3 years ago

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Marshall drove to work in rush hour traffic, going just 27 miles in 1 hour and 20 minutes. Later that day, he left work early to

iragen [17]

Answer:

The average speed of Marshall is 29.7 mph

Step-by-step explanation:

Given;

distance traveled to work, d₁ = 27 miles

distance traveled back home, d₂ = 27 miles

initial time taken, t₁ = 1 hour and 20 minutes

final time taken, t₂ = 29 minutes

Total distance traveled, d = d₁ + d₂ = 27 miles + 27 miles = 54 miles

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8 0

2 years ago

Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v

Veronika [31]

Answer:

$\text {CI} = (60.54, \: 81.46)\\\\$

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

$\bar{x} = \$71$

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$s = \$ 22.35$

The confidence interval is given by

$\text {confidence interval} = \bar{x} \pm MoE\\\\$

Where the margin of error is given by

$$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and $t_{\alpha/2}$ is the t-score corresponding to a 95% confidence level.