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Mnenie [13.5K]
3 years ago
6

Choose the expression that has 5 as an exponent, n as a base, and 7 as a coefficient ​

Mathematics
1 answer:
kow [346]3 years ago
5 0

Answer:

Step-by-step explanation:

7n^5

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1/3n-7/12=-3/8 n=5/72 n=-5/72 n=5/8 n=-2 7/8
prisoha [69]

Given the equation;

\frac{1}{3}n-\frac{7}{12}=-\frac{3}{8}

To solve, let us multiply through by the least common multiple of the the denominator of the three fractions wich is 24;

3 0
1 year ago
What is the total number of rabbits in the neighborhood in year 2
lawyer [7]

Answer:

6

Step-by-step explanation:

5 0
3 years ago
Plz Plz help its hard
Katena32 [7]

Answer:

Third answer! Data varies!

3 0
3 years ago
Consider the expression. (StartFraction 2 m Superscript negative 1 baseline n Superscript 5 Baseline Over 3 m Superscript 0 Base
suter [353]

Answer:

The correct option is option (3) 4 ÷ 25.

Step-by-step explanation:

The expression in terms of <em>m</em> and <em>n</em> is:

F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}

Exponent rule of division:

a^{x}\div a^{y}=a^{x-y}

Compute the value of the expression for <em>m</em> = -5 and <em>n</em> = 3 as follows:

F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}

F(-5,3)=[\frac{2\csdot (-5)^{-1}\cdot (3)^{5}}{3\cdot (-5)^{0}\cdot (3)^{4}}]^{2}

             =\{\frac{2}{3}\times [(-5)^{-1-0}\times (3)^{5-4}}]\}^{2}\\\\=\{\frac{2}{3}\times \frac{-1}{5}\times 3\}^{2}\\\\=\{-\frac{2}{5}\}^{2}\\\\=\frac{4}{25}

Thus, the correct option is option (3) 4 ÷ 25.

8 0
3 years ago
Read 2 more answers
If 3(11x-18y)=6(x+y)-3x-10y <br> what is the ratio of x to y?
exis [7]

Answer: 3:5

Step-by-step explanation:

33x-54y=6x+6y-3x-10y

33x-54y=3x-4y

30x=50y

3x=5y

7 0
3 years ago
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