Answer:
yes I try but not any solution come
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We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
Answer:
(6-2)/4
Step-by-step explanation:
Make sure you have the parenthesis
Answer:
y = -4x+14
Step-by-step explanation:
First find the slope
m = (y2-y1)/(x2-x1)
m = (2-10)/(3-1)
=-8/2
= -4
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
y = -4x+b
Substitute a point into the equation
10 = -4(1)+b
Add 4 to each side
14 = b
y = -4x+14
Answer:
0
Step-by-step explanation:
3x - 9 if x = 3
Substitute:
3(3) - 9 =
9 - 9 = 0
This can be written as a function: f(x) = 3x - 9
f(3) = 3x - 9
f(3) = 3(3) - 9
f(3) = 9 - 9
f(3) = 0
-Chetan K