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hodyreva [135]
3 years ago
14

Whats -99/-11 help please

Mathematics
2 answers:
Svetllana [295]3 years ago
7 0
Poѕιтιve 9 вecaυѕe ιғ yoυ dιvιde or мυlтιply тwo negaтιveѕ or dιvιde ιт wιll gιve yoυ poѕιтιve anѕwer aѕ well aѕ 2 poѕιтιveѕ wιll gιve yoυ a poѕιтιve nυмвer aѕ yoυr anѕwer
mylen [45]3 years ago
7 0
Both -99 and -11 are negative numbers. And when dividing 2 negative numbers, the answer is strictly positive. So -99/-11 will be positive. To get the answer you do some easy calculus and you get -99/-11 = 9; Hope this Helps! :)
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Encuentre el resultado de la diferencia de las fracciones: 9 /12 - 2/3=​
Veronika [31]

Responder:

1/12

Explicación paso a paso:

Entonces multiplicamos 9 por 3 y obtenemos 27.

Luego multiplicamos 2 por 12 y obtenemos 24.

A continuación, le damos a ambos términos nuevos denominadores: 12 × 3 = 36.

Así que ahora nuestras fracciones se ven así:

27

36

-

24

36

Paso 2

Dado que nuestros denominadores coinciden, podemos restar los numeradores.

27 - 24 = 3

Entonces la respuesta es:

3

36

Paso 3

Por último, necesitamos simplificar la fracción, si es posible. ¿Se puede reducir a una fracción más simple?

Para averiguarlo, intentamos dividirlo por 2 ...

¡No! Así que ahora probamos con el siguiente número primo mayor, 3 ...

¿Son tanto el numerador como el denominador divisibles por 3? ¡Sí! Entonces lo reducimos:

3

36

÷ 3 =

<u>1/12 </u>

8 0
3 years ago
Alex is 4 years younger than 2 times his sister's age. Write a rule that represents Alex's age x as a function of his sister's a
Vesna [10]

Answer:

y = 2x - 4; Alex is 18.

Step-by-step explanation:

Since Alex is 4 years younger than 2 times his sister's age, and his sister is y and Alex is x, the function of y to x must be y = 2x - 4.

According to the rule, if Alex's sister is 11, Alex is 2 times that minus four. If you calculate that, you get

11 * 2 = 22

22 - 4 = 18

So Alex is 18 if his sister is 11.

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3 years ago
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Answer:

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Step-by-step explanation:

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lilavasa [31]

Answer:

Step-by-step explanation:

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For the answer to the question above,
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