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Serjik [45]
3 years ago
8

Which line from the excerpt is an example of objective language? In the course of the construction of the Bridge a number of liv

es have been lost. Does it not sometimes seem as though every work of enduring value . . . must needs be purchased at the cost of human life? Let us recall with kindness at this hour the work of those who labored here faithfully unto the death . . . Let us give our meed of praise to-day to the humblest workman who has here done his duty well . . .
Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0

Answer:

C

Step-by-step explanation:

The answer is C

You might be interested in
Reuben can type 48 words in 8 minutes what is the rate in words per minute ?
Sauron [17]

Answer:

6 words per minute.

Step-by-step explanation:

48 divided by 8 is 6 .

5 0
3 years ago
(Translate each sentence into a formula)
Brilliant_brown [7]

Answer:

A=πr2

THIS IS THE ANSWER

PLEASE MARK BRAINLIEST!!!!!

4 0
3 years ago
Find the inverse of the following matrix without using a calculator 1-1 2 -3 2 1 0 4 - 25
Artist 52 [7]

Answer:

18  -(17/3)   (5/3)

25  (25/3)  (7/3)

4    (4/3)     (1/3)

Step-by-step explanation:

You can solve this problem by using the Gauss-Jordan method.

You have the original matrix and then the Identity matrix.

So:

Original              Identity

1 -1 2                    1 0 0

-3 2 1                   0 1 0

0 4 -25                0 0 1

By the Gauss-Jordan method, in the original place you will have the identity and in the place that the identity currently is you will have the inverse matrix:

So, let's start by setting the first row element to 0 in the second and the third line.

The first row element of the third line is already at zero, so no changes there. In the second line, we need to do:

L2 = L2 + 3L1

So now we have the following matrixes.

1 -1 2        |            1 0 0

0 -1 7       |            3 1 0        

0  4 -25   |            0 0 1

Now we need the element in the second line, second row to be 1. So we do:

L2 = -L2

1 -1 2        |            1 0 0

0 1 -7       |            -3 -1 0        

0  4 -25   |            0 0 1

Now, in the second row, we need to make the elements at the first and third line being zero. So, we have the following operations:

L1 = L1 + L2

L3 = L3 - 4L2

Now our matrixes are:

1 0 -5       |            -2 -1 0

0 1 -7       |            -3 -1 0        

0 0 3       |            12 4 1

Now we need the element in the third line, third row being one. So we do:

L3 = -L3

1 0 -5       |            -2  -1     0

0 1 -7       |            -3  -1      0        

0 0 1       |            4    (4/3) (1/3)

Now, in the third row, we need the elements in the first and second line being zero. So we do:

L1 = L1 + 5L3

L2 = L2 + 7L3

So we have:

1 0 0 |       18  -(17/3)   (5/3)

0 1 0 |       25  (25/3)  (7/3)

0 0 1 |       4    (4/3)     (1/3)

So the inverse matrix is:

18  -(17/3)   (5/3)

25  (25/3)  (7/3)

4    (4/3)     (1/3)

4 0
3 years ago
Based on information from Harper’s Index, 37% of adult Americans believe in Extraterrestrials. Out of a random sample of 100 adu
san4es73 [151]

Answer:

z(s)  is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

Step-by-step explanation:

We have a prortion test.

P₀  =  37 %         P₀  = 0,37

sample size  =  n  =  100

P sample proportion   =   P  = 47 %        P  =  0,47

confidence interval  95 %

α  =   0,05  

One tail-test  (right tail) our case is to show if sample give enough information to determine if proportion of individual who attended college is higher than the proportion found by Harper´s index.

1.-Hypothesis:

H₀      null hypothesis                        P₀  =  0,37

Hₐ  alternative hypothesis                P₀  >  0,37

2.-Confidence interval 95 %

α  =   0,05        and    z(c)  =  1.64

3.-Compute of z(s)

z(s)  =  [  P  -  P₀  ]  /√(P₀Q₀/n) ]  

z(s)  =  [ (  0,47  -  0,37  ) /  √0.37*0,63/100

z(s)  = 0,1 /√0,2331/100     ⇒   z(s)  = 0,1 /0,048

z(s)  = 2.08

4.-Compare  z(s)   and  z(c)

z(s) > z(c)        2.08  > 1.64

5.-Decision:

z(s)  is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

5 0
3 years ago
Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k
ch4aika [34]

Given

\vec v =  f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k

the curl of \vec v is

\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

7 0
3 years ago
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