5a+7=4a+4 solve for a.
2 answers:
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Answer:
The translation from triangle IJK to triangle I'J'K' is which is 2 units to the right and 6 units up
Step-by-step explanation:
The coordinates of triangle JKI are;
J has coordinates (1, - 1)
K has coordinates (1, - 4)
I has coordinates (-3, - 2)
While, the coordinates of translation triangle J'K'I' are;
J' has coordinates (3, 5)
K' has coordinates (3, 2)
I' has coordinates (-1, 4)
Which give the translation as follows
Translation in the y-coordinate (y values);
For J = 5 - (-1) = 6
For K = 2 - (-4) = 6
For I = 4 - (-2) = 6
Translation in the x-coordinate (x values);
For J = 3 - 1 = 2
Therefore, the translation from triangle IJK to triangle I'J'K' is T(2, 6) which is 2 units to the right and 6 units up
I'm thinking this is what the problem looks like: 
. The first thing to do is to move the 
over to the other side because it has a common denominator with the other side. Doing that and at the same time combining them over their common denominator looks like this: 
. The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4). Distributing through the parenthesis is 12 - 3x = -4x + 16. Solving for x gives us x = 4. Of course when we sub a 4 back in for x we get real problems, don't we? Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.