Question

What is the simplest form of 3^ √27t^9/729?

Answer 1

Answer:

the third option is correct

Step-by-step explanation:

:)

Answer 2

Answer:

$\frac{t^{3} }{3}$

Step-by-step explanation:

$\sqrt[3]{\frac{27t^{9} }{729} }$ 27 is a perfect cube for $3^{3}$ and 729 is a perfect cube for $9^{3}$

$\sqrt[3]{\frac{3^{3} t^{9} }{9^{3} } }$  now you can pull out the numbers from under the root, for t (divide the exponent by 3)

$\frac{3}{9}$$t^{3}$ now simply to $\frac{t^{3} }{3}$