(−m)(n)p(3m−5n+7p)
=((−m)(n)p)(3m+−5n+7p)
=((−m)(n)p)(3m)+((−m)(n)p)(−5n)+((−m)(n)p)(7p)
=−3m^2np+5mn^2p−7mnp^2
You didn't include the formula.
Given that there is no data about the mass, I will suppose that the formula is that of the simple pendulum (which is only valid if the mass is negligible).
Any way my idea is to teach you how to use the formula and you can apply the procedure to the real formula that the problem incorporates.
Simple pendulum formula:
Period = 2π √(L/g)
Square both sides
Period^2 = (2π)^2 L/g
L = [Period / 2π)^2 * g
Period = 3.1 s
2π ≈ 6.28
g ≈ 10 m/s^2
L = [3.1s/6.28]^2 * 10m/s^2 =2.43 m
I hope this helps you.
The walls are vertical so the angle opposite X would be a right angle which is 90 degrees.
X would be 180 - 90 - 35 = 55 degrees
X and 2y - 5 are complementary angles which add together to equal 90:
2y - 5 + 55 = 90
Simplify:
2y +50 = 90
Subtract 50 from both sides:
2y = 40
Divide both sides by 2:
y = 20
Answer:
that help
Step-by-step explanation:
10h+27+−27=c+−27
10h=c−27
10h10=c−2710
h=110c+−2710
Answer:
h=110c+−2710
Answer:
<em>Answer is </em><em>given below with explanations</em><em>. </em>
Step-by-step explanation:

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