Answer:
Using the t-distribution, the 99% confidence interval for the true average number of alcoholic drinks all UF female students (over 21) have in a one week period is (3.25, 4.85).
We have the standard deviation for the sample, thus, the t-distribution is used to solve this question.
First, we find the number of degrees of freedom, which is the sample size subtracted by 1, thus:
Then, using a calculator, with and 169 df, we have that the two-tailed critical value is .
The margin of error is:
In this problem, , then:
The confidence interval is:
In this problem, , then:
The confidence interval is (3.25, 4.85).
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
You cannot have two or more domains.
'
3 appears twice and is located in the x axis, which is basically the domain.
Hope this helps
When asked these kinds of problems you find the discriminate and use that to tell if you have one , two or zero real solutions.
The formula for the discriminate is b^2 - 4ac. I hope that looks familiar because it is the inside part of the quadratic formula. (the part under the radical)
so if your answer is greater than zero you have two solutions
if your answer is equal to zero you have one solution
if your answer is less than zero you have no real solutions it will be a complex solution.
So lets apply all that to your question:
5^2 - 4(1)(7) = -3
so your answer would be B no real-number solution.
I think of these in terms of "short side", "long side" and "hypotenuse." The proportions will be true that equate the ratios of corresponding sides.
I is (long side of CDB)/(short side of CDB) = (long side of BDA)/(short side of BDA)
These are corresponding sides, so the proportion is <em>true</em>.
II is (hypotenuse of CBA)/(long side of CBA) = (long side of CBA)/(hypotenuse of CBA)
This proportion equates a value to its inverse, so is <em>false</em> (since the triangle has non-zero area)
III is (long side of CBA)/(short side of CBA) = (hypotenuse of CBD)/(long side of CBD)
The sides involved here are not corresponding, so this is <em>false</em>.
IV is (long side of CDB)/(hypotenuse of CDB)/(long side of BDA)/(hypotenuse of BDA)
These are corresponding sides, so the proportion is <em>true</em>.
The appropriate choice is ...
... a. I and IV only
Answer:
42.5
Step-by-step explanation:
Its the first one