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kykrilka [37]
3 years ago
15

Simon makes 8 towers of 10 blocks each. Ron makes 9 towers of 10 blocks each. How many blocks did they use?

Mathematics
2 answers:
notsponge [240]3 years ago
7 0
they used 107 blocks!
Lady_Fox [76]3 years ago
3 0
They used 170 blocks
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A regular pentagonal prism has a volume of 2,850 cubic millimeters. what is the height of the prism? a regular pentagonal prism
zlopas [31]

Answer:

Height = 19mm.

Step-by-step explanation:

Area of a regular polygon =  (A * P) / 2 where A = side / (2 * Tan (π / N)) where, N = Number of sides, A = Apothem,  P = Perimeter.

Here A = 5, P = 5*12 = 60 so

Area  of the base  = (5 * 60) / 2 = 150 mm^2.

Volume = area base * height so

Height = volume / area of base

            = 2850 / 150

            = 19 mm.

5 0
1 year ago
Point P is at the origin. Then Point P is moved 4 units to the right and 5 units up.
taurus [48]

Answer:

Step-by-step explanation:

The origin (x,y) is (0,0)

If its moved four units right you must add 4 to the x coordinate giving you (4,0)

Then it is moved up by 5, so you must add 5 to the y coordinate giving you

(4,5)

8 0
2 years ago
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Can y'all help me with this please
asambeis [7]
12 times 35 times 28=  980..... im not sure
5 0
2 years ago
Let c be parametrized by x = et sin (10t) and y = et cos (10t) for 0 ≤ t ≤ 2. find the length l of
marysya [2.9K]
C:x(t)=e^t\sin10t;\,y(t)=e^t\cos10t;\,0\le t\le2

\displaystyle\int_0^2\sqrt{x'(t)^2+y'(t)^2}\,\mathrm dt
\displaystyle=\int_0^2\sqrt{(e^t\sin10t+10e^t\cos10t)^2+(e^t\cos10t-10e^t\sin10t)^2}\,\mathrm dt
\displaystyle=\int_0^2e^t\sqrt{\sin^210t+20\sin10t\cos10t+100\cos^210t+\cos^210t-20\sin10t\cos10t+100\sin^210t}\,\mathrm dt
=\displaystyle\int_0^2e^t\sqrt{1+100}\,\mathrm dt
=\displaystyle\sqrt{101}(e^2-1)
7 0
3 years ago
Trigonometry (ASAP) (Urgent) ​
Olin [163]

Answer:

h = 1.403733341286

Step-by-step explanation:

17.

the triangle of sides ‘l’ and ‘l-h’ is a right angled triangle.

Then

\cos \theta =\frac{l-h}{l}

Then

l\cos \theta =l-h

Then

h=l-l\cos \theta

18.

For l = 6  and  θ = 40 :

h=l-l\cos \theta

  = 6-6cos(40)

  = 1.403733341286

8 0
1 year ago
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