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antiseptic1488 [7]
3 years ago
13

Is 12 a natural, rational, or integ er number

Mathematics
1 answer:
MrRa [10]3 years ago
4 0
Yes.  All of those.  Also a real number.
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If f(x) = 4x + 12 is graphed on a coordinate plane, what is the y-intercept of the graph?
Tatiana [17]

Answer:  y=12

Step-by-step explanation:

the y-intercept of the graph when : x=0

f(0) =4(0)+12 = 12

8 0
3 years ago
Read 2 more answers
The area of Sahara desert is 7 times the area of the Gobi Desert. If the sum of their areas is 4,000,000 square miles, find the
ryzh [129]
X=area of Sahara.
y=area of the Gobi Desert.
We suggest this system equations:
x+y=4000000
x=7y
solve by susbstitution method.
(7y)+y=4,000,000
8y=4,000,000
y=4,000,000 / 8=500,000

x=7y
x=7(500,000)=3,500,000

The area of Sahara=3,500,00 miles².
The area of the Gobi Desert=500,000 miles²

To check:
Te sum of their areas is : 3,500,000 miles²+500,000 miles²=4,000,000 miles²
Te area of sahara (3,500,000 miles²) is 7 times the area of the Gobi Desert (7*500,000 miles²=3,500,000 miles²).
4 0
3 years ago
7 lbs of sour candies cost $7.00. What is the unit price?
grandymaker [24]

Answer:

$1 per lb

Step-by-step explanation:

If you divide the cost by the amount you are getting, then you get the unit rate. So, since 7 divided by 7.00 is 1.00, then the cost per pound is $1.00

7 0
3 years ago
Find -3a2 - b3 + 3c2 - 2b3 if a = 2, b = -1, and c = 3
Studentka2010 [4]
If you would like to solve - 3 * a^2 - b^3 + 3 * c^2 - 2 * b^3, if a = 2, b = -1, c = 3, you can calculate this using the following steps:

a = 2, b = -1, c = 3
- 3 * a^2 - b^3 + 3 * c^2 - 2 * b^3 = - 3 * 2^2 - (-1)^3 + 3 * 3^2 - 2 * (-1)^3 = - 3 * 4 - (-1) + 3 * 9 - 2 * (-1) = - 12 + 1 + 27 + 2 = 18

The correct result would be 18.

6 0
3 years ago
Read 2 more answers
Find the exact value of the trigonometric expression given that sin u = − 8 17 and cos v = − 24 25 . (Both u and v are in Quadra
Rashid [163]

Answer: sin u = -5/13 and cos v = -15/17

Step-by-step explanation:

The nice thing about trig, a little information goes a long way. That’s because there is a lot of geometry and structure in the subject. If I have sin u = opp/hyp, then I know opp is the opposite side from u, and the hypotenuse is hyp, and the adjacent side must fit the Pythagorean equation opp^2 + adj^2 = hyp^2.

So for u: (-5)^2 + adj^2 = 13^2, so with what you gave us (Quad 3),

==> adj of u = -12 therefore cos u = -12/13

Same argument for v: adj = -15,

opp^2 + (-15)^2 = 17^2 ==> opp = -8 therefore sin v = -8/17

The cosine rule for cos (u + v) = (cos u)(cos v) - (sin u)(sin v) and now we substitute: cos (u + v) = (-12/13)(-15/17) - (-5/13)(-8/17)

I am too lazy to do the remaining arithmetic, but I think we have created a way to approach all of the similar problems.

3 0
3 years ago
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