All categories

3 years ago

BRAINLIEST FOR FIRST ANSWER! PLS GIVE FULL EXPLANATION :)

Mathematics

1 answer:

S_A_V [24]3 years ago

6 0

Answer:

∠MEJ=25°

Step-by-step explanation:

step 1

Find the value of x

we know that

arc LJ+arc KM+arc KL+arc MJ=360° ----> complete circle

substitute the values

(4x+50)°+6x°+(x+10)°+4x°=360°

solve for x

(15x+60)°=360°

x=300°/15=20°

step 2

Find the measure of angle MEJ

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

∠MEJ=(1/2)[arc MJ-arc KL]

arc MJ=4(20°)=80°

arc KL=20°+10°=30°

substitute the values

∠MEJ=(1/2)[80°-30°]=25°

You might be interested in

Please help! The girls' gym teacher needs to purchase

hram777 [196]

Well the teacher would only get $15 but we don’t know how much the balls cost so you can’t make an expression

5 0

2 years ago

HELP what is 3( 2+5) - 5 (3) + 8

neonofarm [45]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Can I have workings out plz x

mixer [17]

Answer:

pretty sure the answer is 432 cm2 not sure im in a rush

Step-by-step explanation:

8 0

2 years ago

What is the value of x? enter your answer in the box.

Mamont248 [21]

Answer:

if 9x8 =72

then 56/8= 7

x=7

8 0

2 years ago

39-50 find the limit.<br> 41. <img src="https://tex.z-dn.net/?f=%5Clim%20_%7Bt%20%5Crightarrow%200%7D%20%5Cfrac%7B%5Ctan%206%20t

Katyanochek1 [597]

Write tan in terms of sin and cos.

$\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}$

Recall that

$\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1$

Rewrite and expand the given limand as the product

$\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)$

Then using the known limit above, it follows that

$\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}$

4 0

1 year ago