Question

What is the equation of the line that passes through (-2, 2) and (1, -4)?

Answer 1

Answer:

y = - 2x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁  = (- 2, 2) and (x₂, y₂ ) = (1, - 4)

m = $\frac{-4-2}{1+2}$ = $\frac{-6}{3}$ = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 2, 2), then

2 = 4 + c ⇒ c = 2 - 4 = - 2

y = - 2x - 2 ← equation of line