The equivalent fractions
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10 question of spelling words and 16 questions of vocabulary are present
<em><u>Solution:</u></em>
Let "x" be the number of spelling word questions
Let "y" be the number of vocabulary word question
<em><u>There is a total of 26 questions. Therefore, we get</u></em>
number of spelling word questions + number of vocabulary word question = 26
x + y = 26 --------- eqn 1
<em><u>There are spelling word questions that worth 2 points each and vocabulary word question worth 5 points each</u></em>
The language arts test is worth 100 points
Therefore, we frame a equation as:
number of spelling word questions x 2 + number of vocabulary word question x 5 = 100
2x + 5y = 100 --------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
x = 26 - y ------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
2(26 - y) + 5y = 100
52 - 2y + 5y = 100
3y = 100 - 52
3y = 48
<h3>y = 16</h3><em><u>Substitute y = 16 in eqn 3</u></em>
x = 26 - 16
<h3>x = 10</h3>Thus 10 question of spelling words and 16 questions of vocabulary are present