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DiKsa [7]
3 years ago
7

Find, in terms of π, the surface area of a sphere generated by rotating a semicircle of radius 6 inches about its diameter.

Mathematics
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

144\pi in^2

Step-by-step explanation:

Given

Shape: Circe

Radius = 6 inches

Required

What is the surface area of a sphere when the circle

When a circle is rotated about its diameter, the resulting sphere maintains the same radius and diameter as the circle, before rotation;

This implies that

Radius [of sphere] = 6 inches

Surfare\ Area = 4\pi r^2

Substitute 6 for r

Surfare\ Area = 4\pi* 6^2

Surfare\ Area = 4\pi* 6 * 6

Surfare\ Area = 4\pi*36

Surfare\ Area = 144\pi

<em>Hence, the surface area of the resulting sphere is 144 pi inches square</em>

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pickupchik [31]

First, distrbute -3 to both -4y and 3

-3(-4y) = 12y  -> note that two negatives multiplied = one positive answer

-3(3) = -9      -> note that one negative and one positive = one negative answer

12y - 9 + 7y  -> combine like terms

12y + 7y - 9

19y - 9 -> answer

Your answer is 19y - 9

hope this helps

~Crystal

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3 years ago
Use Ohm’s law to find the resistance of the light bulb if you had a 20 volt battery and 0.57 amps of current. Show your work for
aleksley [76]
For this case we have the following equation:
 V = I * R
 Where,
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 I: current
 R: resistance
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3 years ago
Can someone help me with this?
IgorC [24]
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7 0
3 years ago
What is 3 4/9 as a decimal
goldfiish [28.3K]

Answer: 3.44

Step-by-step explanation:

Step 1: Multiply the whole number by the denominator:

3 × 9 = 27

Step 2: Add the product you got in Step 1 to the numerator:

27 + 4 = 31

Step 3: Divide the sum from Step 2 by the denominator:

31 ÷ 9 = 3.444444

The answer to 3 4/9 in decimal form is displayed below:

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3 0
2 years ago
Cot^2x csc^2x + 2 csc^2x –cot^2 = 2
kow [346]

Answer:

x = π/2 + πk

Step-by-step explanation:

cot² x csc² x + 2 csc² x − cot² x = 2

Multiply both sides by sin² x:

cot² x + 2 − cos² x = 2 sin² x

Add cos² x to both sides:

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Pythagorean identity:

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Subtract 1 from both sides:

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Pythagorean identity:

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1 = sin⁴ x

Take the fourth root:

sin x = ±1

Solve for x:

x = π/2 + 2πk, 3π/2 + 2πk

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x = π/2 + πk

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3 years ago
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