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3 years ago

Given a typical magnetic hard drive with five platters, answer the following:

Computers and Technology

1 answer:

Nataly_w [17]3 years ago

5 0

Answer:

Given the number of platters =5

A. Hence, the number of recording surface =10

B. number of read-write heads =10

C. Number of arms holding the read-write heads = 10

Explanation:

We know that number of recording surface = 2 *( number of platters)

= 2*5=10

And the number of read-write heads = number of recording surface= 10

Also, number of arms holding the read-write head = one for each read-write head= 10

And hence, the above answer.

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C program for finding size of different data types

#include <stdio.h>

//driver function

int main()

{

int a; //declaring a of type int

float b; //declaring b of type float

double c; //declaring c of type double

char d; //declaring d of type char

long e; //declaring e of type long

long long f; //declaring f of type longlong

unsigned g; //declaring g of type unsigned

// Sizeof operator is used to evaluate the size of a variable

printf(" int data type contains: %lu bytes\n",sizeof(a));/*Finding size of int */

printf("float data type contains : %lu bytes\n",sizeof(b));/*Finding size of float */

printf("double data type contains: %lu bytes\n",sizeof(c));/*Finding size of double */

printf("char data type contains: %lu byte\n",sizeof(d));/*Finding size of char */

printf("long data type contains: %lu byte\n",sizeof(e));/*Finding size of long*/ printf("longlong data type contains: %lu byte\n",sizeof(f));/*Finding size of longlong */

printf("unsigned data type contains: %lu byte\n",sizeof(g)); /*Finding size of unsigned */

return 0;

}

Output

int data type contains: 4 bytes

float data type contains : 4 bytes

double data type contains: 8 bytes

char data type contains: 1 byte

long data type contains: 8 byte

longlong data type contains: 8 byte

unsigned data type contains: 4 byte

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