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3 years ago

Write a public interface named Test with the following behavior:

Computers and Technology

1 answer:

enyata [817]3 years ago

8 0

Answer:

The code to this question can be given as:

Code:

public interface Test //define interface

{

public abstract Duration getDuration(); //define method

getDuration.

public abstract Result check(int a);

//define method

check .

public abstract double getScore();

//define method getScore.

}

Explanation:

In the above code, we define an interface that is "Test" inside an interface, we define three methods that can be defined as:

First, we define a method that is "getDuration" that method returns Duration as an object.
Second, we define a method that is "check" this method accepts an integer parameter that is a and return Result.
The third method is "getScore" this method will return a double value.

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3 years ago

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3 years ago

Read 2 more answers

Algebraic concepts that include certain words and phrases and

Veseljchak [2.6K]

Answer:

Boolean Operators

Explanation:

When performing a boolean search, boolean operators allow users to combine keywords with operators (or modifiers) such as AND, NOT and OR to further produce more relevant results.

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3 years ago

Locker doors There are n lockers in a hallway, numbered sequentially from 1 to n. Initially, all the locker doors are closed. Yo

kow [346]

Answer:

// here is code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables

int n,no_open=0;

cout<<"enter the number of lockers:";

// read the number of lockers

cin>>n;

// initialize all lockers with 0, 0 for locked and 1 for open

int lock[n]={};

// toggle the locks

// in each pass toggle every ith lock

// if open close it and vice versa

for(int i=1;i<=n;i++)

{

for(int a=0;a<n;a++)

{

if((a+1)%i==0)

{

if(lock[a]==0)

lock[a]=1;

else if(lock[a]==1)

lock[a]=0;

}

cout<<"After last pass status of all locks:"<<endl;

// print the status of all locks

for(int x=0;x<n;x++)

{

if(lock[x]==0)

{

cout<<"lock "<<x+1<<" is close."<<endl;

}

else if(lock[x]==1)

{

cout<<"lock "<<x+1<<" is open."<<endl;

// count the open locks

no_open++;

}

// print the open locks

cout<<"total open locks are :"<<no_open<<endl;

return 0;

}

Explanation:

First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.

Output:

enter the number of lockers:9

After last pass status of all locks:

lock 1 is open.

lock 2 is close.

lock 3 is close.

lock 4 is open.

lock 5 is close.

lock 6 is close.

lock 7 is close.

lock 8 is close.

lock 9 is open.

total open locks are :3

5 0

3 years ago