Which type of number is -4? Integer Irrational number Radical Whole number

Mathematics

1 answer:

Deffense [45]2 years ago

6 0

-4 is an integer. hope this helped!

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olganol [36]

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3 years ago

What is true of the function g(x)=-2x^2+5?

mart [117]

Answer:

C) The variable x represents the independent variable.

Step-by-step explanation:

The given function is $g(x)=-2x^2+5$ .

g(x) is NOT the multiplication of g and x because g is a function of x.

$x$ is the input of the function.

$-2x^2+5$ is the output of the function.

The variable $x$ is called the independent variable because we plug in values of x to find g.

The variable g represents the output of the function NOT the input.

The correct choice is C

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3 years ago

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larisa [96]

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2 years ago

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The wolf population of a park was 200 in the year 200. it increased by 20% from 200 to 2005. it then increased by 15% from 2005

leonid [27]

B
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Neko [114]

$\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
\\\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
-----------------------------\\\\
\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\
-----------------------------\\\\
\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}$

$\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}
\\\\\\
\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0$

4 0

3 years ago