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Greeley [361]
3 years ago
7

The formula to find the area of the walls of a rectangular room is A=2h (l+b), h is wall height, l is room length, and b is room

breadth. The area of doors and windows are ignored.
Question - Using the formula find the wall area if the room length is 8m, breadth is 6m and height is 2.5 m.
Sorry but I have NO clue :(
Mathematics
1 answer:
Allisa [31]3 years ago
8 0
Problems are very often written in a confusing way. This one couldn't possibly have been
written any more clearly.  Sooner or later, you have to stop telling yourself that you have
no clue, settle down, and carefully read the words that are right there on the page.

I'll tell you one more detail that's not in the problem:  "breadth" means "width".
 
Now.  The problem clearly tells you all of these things, in this exact order:

=>  Area of the walls = (2 x height) x (length + width)

=>  length = 8m
=>  width = 6m
=>  height = 2.5m 

Is there a reason you can't take the numbers for length, width, and height,
and write them in the formula for the area ?  Do I have to do all the work ?

Area = (2 x height) x (length + width)

Area = (2 x 2.5m ) x ( 8m    +   6m  )

Do the arithmetic inside the parentheses:

Area = (    5m     ) x (     14m          )

Do the multiplication:

Area = <u>70 m² .</u>

You will never see a problem that comes any closer to answering itself <em>for </em>you.
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Answer:

90

Step-by-step explanation:

circumference of total circle = 16 pi

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1 / 4 =25%

1/4 * 360 = 90

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Natasha_Volkova [10]
Your answer is C :) blessings
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Find the solution set of the inequality
Brilliant_brown [7]

<u>Answer:</u>

\boxed{\textsf{ Hence the solution set is$ \bf{\bigg( \dfrac{33}{4},\infty \bigg) }$}}.

<u>Step-by-step explanation:</u>

A inequality is given to us and we need to find the solution set. So the given inequality to us is ,

  • -4x + 35 >2

\bf\implies -4x + 35 > 2 \\\\\bf\implies -4x > 2-35 \\\\\bf \implies -4x > -33 \\\\\bf \implies x >\dfrac{-33}{-4}\\\\\bf \implies x > \dfrac{33}{4} \\\\\bf\implies \boxed{\pink{\bf x \in \bigg(\dfrac{33}{4}, \infty \bigg) }}

<h3><u>★</u><u> </u><u>Hence </u><u>the </u><u>solution</u><u> </u><u>set </u><u>is </u><u>x </u><u>€</u><u> </u><u>(</u><u> </u><u>3</u><u>3</u><u>/</u><u>4</u><u> </u><u>,</u><u> </u><u>∞</u><u> </u><u>)</u><u>.</u></h3>
3 0
3 years ago
Arelli uses 6.9 pints of white paint and blue paint to paint her bedroom walls. 3/4 of this amount is white paint, and the rest
Reika [66]

Answer:

1.73

Step-by-step explanation:

Arelli use 6.9 pints of white and blue paints for her bedroom

3/4 of this amount is white

3/4

= 0.75×100

= 75

100-75

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Amount of blue paint is

25/100×6.9

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4 0
2 years ago
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
avanturin [10]
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900

There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20

The price of an advance ticket was 20.
The price of a same-day ticket was 15.
6 0
3 years ago
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