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Greeley [361]
3 years ago
7

The formula to find the area of the walls of a rectangular room is A=2h (l+b), h is wall height, l is room length, and b is room

breadth. The area of doors and windows are ignored.
Question - Using the formula find the wall area if the room length is 8m, breadth is 6m and height is 2.5 m.
Sorry but I have NO clue :(
Mathematics
1 answer:
Allisa [31]3 years ago
8 0
Problems are very often written in a confusing way. This one couldn't possibly have been
written any more clearly.  Sooner or later, you have to stop telling yourself that you have
no clue, settle down, and carefully read the words that are right there on the page.

I'll tell you one more detail that's not in the problem:  "breadth" means "width".
 
Now.  The problem clearly tells you all of these things, in this exact order:

=>  Area of the walls = (2 x height) x (length + width)

=>  length = 8m
=>  width = 6m
=>  height = 2.5m 

Is there a reason you can't take the numbers for length, width, and height,
and write them in the formula for the area ?  Do I have to do all the work ?

Area = (2 x height) x (length + width)

Area = (2 x 2.5m ) x ( 8m    +   6m  )

Do the arithmetic inside the parentheses:

Area = (    5m     ) x (     14m          )

Do the multiplication:

Area = <u>70 m² .</u>

You will never see a problem that comes any closer to answering itself <em>for </em>you.
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Answer:

10%

Step-by-step explanation:

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The multiples of 5 are 5, 10, 15, 20 , 25, and so on

It is evident that the only one that matches up between 1-10 is 10.

There are 10 options, and our chances are random. There is only 1 option for it to be a multiple of both 2 and 5. Therefore, the probability is 1/10, or 10%

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Step-by-step explanation:

A

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Which of the following points is in the solution set of y&gt;-x² + 5?
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= 272 and
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In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir
Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}= p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0204^{2}).

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.96

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0306^{2}).

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.31

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0
3 years ago
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