What is the radius of the circle given by the equation (x-2)^2+y^2=14

1 answer:

8 0

The general equation of a circle is
(x-a) ^ 2 + (y-b) ^ 2 = r ^ 2
for this case the values of a and b are
a = 2
b = 0
The radius of the circle is
r ^ 2 = 14
r = (14) ^ (1/2) = 3.74

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a² - 2a - b² = 0
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To find :-

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Taking second equation:-

2b + 2ab = 0
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