Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
-11/4
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(2-57)/(23-3)
m=-55/20
simplify
m=-11/4
Please mark me as Brainliest if you're satisfied with the answer.
Answer:
Option C. is the correct answer
Step-by-step explanation:
Choose any value of x and find the values of y. Then plot a graph using all that points. These will neither parallel nor perpendicular.
4. 8+12=20
4 (2+3)
First you add 2+3 and get 5
Next, since the 5 is now in the parentheses, it indicates that you have to multiply
Finally, 5 times 4=20
