The piecewise function h(x) is shown on the graph. What is the value of h(2)? −2 −1 0 3
2 answers:
We need to find the value of h(2).
h(2) represents the value of h function for x=2.
We need to check the value of function on the graph where h is 2.
From the graph, we can see for x=2, we have a solid dot for y coordinate at 0 and a hollow dot at y coordinate at 3.
Because hollow dot represents excluded value.
Therefore, we would take y coordinate of solid dot of the graph at x=2.
Therefore, f(2) = 0.
<h3>Correct option is third option, that is 0.</h3>
You might be interested in
Answer:
a. u1≤u2
b P<0.05 rejected H
Step-by-step explanation:
College High School
485 442
534 580
650 479
554 486
550 528
572 524
497 492
592 478
487 425
533 485
526 390
410 535
515
578
448
469
The mean is the average . the sum of number over the number of observation
x1=525
x2=487
s.d1=59.42
s.d2=51.74
n1=16
n2=12
Determine the hypothesis
u1≤u2
find the degree of freedom
25
p-value is the probability of obtaining the value of the test statistics. In the column of t-value in the row df=25
0.025<P<0.05
if the P value is actually less than or the same as the significant level, then the null hypothesis is rejected
P<0.05 rejected H
Answer:
(a) The correct answer is P (CBM) = 0.79.
(b) The probability of selecting an American female who is not red-green color-blind is 0.996.
(c) The probability that neither are red-green color-blind is 0.9263.
(d) The probability that at least one of them is red-green color-blind is 0.0737.
Step-by-step explanation:
The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.
It is provided that 79% of men and 0.4% of women are colorblind, i.e.
P (CBM) = 0.79
P (CBW) = 0.004
(a)
The probability of selecting an American male who is red-green color-blind is, 0.79.
Thus, the correct answer is P (CBM) = 0.79.
(b)
The probability of the complement of an event is the probability of that event not happening.
Then,
P(not CBW) = 1 - P(CBW)
= 1 - 0.004
= 0.996.
Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.
(c)
The probability the woman is not colorblind is 0.996.
The probability that the man is not color- blind is,
P(not CBM) = 1 - P(CBM)
= 1 - 0.004
= 0.93.
The man and woman are selected independently.
Compute the probability that neither are red-green color-blind as follows:
Thus, the probability that neither are red-green color-blind is 0.9263.
(d)
It is provided that a one man and one woman are selected at random.
The event that “At least one is colorblind” is the complement of part (d) that “Neither is Colorblind.”
Compute the probability that at least one of them is red-green color-blind as follows:
Thus, the probability that at least one of them is red-green color-blind is 0.0737.