Answer: 25
Step-by-step explanation: (x-a)² = x² - 2ax + a²
From x² - 10x + k we deduce that 10x = 2·5x and a = 5
Then k = 5²2
Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1
Answer:
02 High Schools would be selected from the stratum with a percent-free-lunch value of 40 less than or equals x.
Step-by-step explanation:
As the sample size needed is 25 and total schools are 100 so this indicate 1 school in each 4 schools is to be selected. This is given as

Now as the schools with percent free lunch are 8 so now

So only 2 schools will be selected in this regard.
Set up a proportion. 6/10 = 9/x. cross multiply so x times 6 = 6x. And 10 times 9 = 90. so 6x=90. Then 90 and 6x divided by 6. which gets you x=15. The 9 ft tall elephant will cast a 15 ft shadow.