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scoray [572]
3 years ago
14

Solve the equation 12+ 0.35×=20.05

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0
12 + 0.35X = 20.05
12 + 0.35X - 12 = 20.05 - 12
0.35X = 8.05 
0.35X/0.35 = 8.05/0.35
X = 23
Hope this helps!! 
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One number is 5 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 492,
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Answer:

The numbers are 56, 280 and 156

Step-by-step explanation:

Let

x -----> the first number

y ----> the second number

z ----> the third number

we know that

y=5x -----> equation A

z=x+100 ----> equation B

x+y+z=492 ----> equation C

Solve the system of equations by substitution

substitute equation B and equation A in equation C and solve for x

x+5x+x+100=492

7x=492-100

7x=392

x=56

<u><em>Find the value of y</em></u>

y=5x -----> y=5(56)=280

<u><em>Find the value of z</em></u>

z=x+100 ----> z=56+100=156

therefore

The numbers are 56, 280 and 156

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