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scoray [572]
3 years ago
14

Solve the equation 12+ 0.35×=20.05

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0
12 + 0.35X = 20.05
12 + 0.35X - 12 = 20.05 - 12
0.35X = 8.05 
0.35X/0.35 = 8.05/0.35
X = 23
Hope this helps!! 
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Quick plz help asap marking brainliest for first answer as long as you include steps !!!
Akimi4 [234]

Answer:

a=2.48

c=9.52

Step-by-step explanation:

a+c=12

4a+7.5c=72.5 Given


a+c=12

-4a-7.5c=-72.5 multiply the equation by negative 1


-3a-6.5c=-60.5 simplify


-3a=-60.5+6.5c add 6.5c to both sides


a=-20.17+2.17c divide it by 3

now you would take that equation and plug it into an equation you already have since you have something to plug in for a, the easiest one to do is a+c=12

(-20.17+2.17c)+c=12 plug in the equation


-20.17+3.17c=12 simplify by solving for c


3.17c=30.17 add 20.17 to both sides


c=9.52 divide both sides by 3.17

now since you have found c, you can plug it in to you equation to solve for a now (use the ones from the second step).  I am using the equation a+c=12.

a+9.52=12 plug in the variable and solve for a


a=2.48 subtract 9.52 to both sides


a=2.48

c=9.52

7 0
3 years ago
Simplify ........ (256y²⁵⁶) ⅛<br>help asap!!!!!​
AVprozaik [17]

Answer:

2y^32

Step-by-step explanation:

Since 2^8 = 256, the eighth root of 256 is 2.

Next, we find the power of y by multiplying 256 and 1/8:  result is 32.

Complete answer:  2y^32

7 0
3 years ago
1. Evaluate: <br>0.234 x 10^2<br><br>​
stellarik [79]

Answer: 23.4 is the answer

3 0
3 years ago
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Helpp lang pooo di ko alam eh..<br>A.P po subject
docker41 [41]

Answer:

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8 0
3 years ago
What is the following product? 3√2(5√8-7√3)
vovangra [49]

Answer:

3√2(5√8-7√3) = 60 - 21√6

Step-by-step explanation:

We need to find the product of  3√2(5√8-7√3). The distributive property states that: A(B+C) = AB + AC.

Then, by using the distributive propertive we have that:

3√2(5√8-7√3) = 3√2 * 5√8 - 3√2 * 7√3 = 15√8√2 - 21√2√3.

Also, we know that: √A√B = √AB. Using this:

15√8√2 - 21√2√3 = 15√16 - 21√6 = 60 - 21√6.

6 0
3 years ago
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