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3 years ago

PleAse help with this question

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

8 0

5 it 5 it 5 555555

Step-by-step explanation:

hope this helped

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Can somebody help me with this problem .. I’ll really appreciate it .

Ira Lisetskai [31]

Answer:

4(4x+3)=19x+9-3x+3

4*4x 4*4 =19x+9-3x+3

16x+12= 16x+12

12=12

8 0

3 years ago

Does anyone know how to do this

pickupchik [31]

You just add or subtract from the x and y

4 0

3 years ago

Giving 15 points for help!

kolezko [41]

Answer: The correct statements are 'The equation 2n = p should be 2p = n' , 'The actual cost of the onions is $3.00 per pound' and 'Potatoes cost $1.50 per pound.'

Step-by-step explanation:

Here, p represents cost of one potato and n represents the cost of one onion.

And, According to the question, He purchases 6 pounds of potatoes, p, and 3 pounds of onions, n, for $18.

Therefore, 6p +3n = 18 ------(1)

And, Onions cost twice as much as potatoes.

Therefore, n= 2p ---------(2)

Putting the values of n from 2) in equation 1),

we get, 6p+3(2p)=18

⇒6p+6p=18 ⇒ 12p =18 ⇒ p = 1.5 dollar.

Thus cost of one potato= $1.5

And cost of one onion = $ 2× 1.5= $ 3.00

Thus with help of above explanation we can say that Options first, third and fifth are correct.

8 0

4 years ago

Read 2 more answers

Machine A can complete a certain job in x hours. Machine B can complete the same job in y hours. If A and B work together at the

scZoUnD [109]

Answer:

$\frac{y}{x+y}$

Step-by-step explanation:

The required answer is the rate at which Machine A works when the two machines are combined.

Note: the rate of doing work is express as

$rate=\frac{1}{time taken} \\$

Hence we can conclude that Machine A working rate is

$machine A=\frac{1}{x} \\$ and machine B working rate is

$machine B=\frac{1}{y} \\$

When the two machine works together, the effective working rate is

$\frac{1}{x}+\frac{1}{y}\\\frac{xy}{x+y}\\$

The fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A

Hence the fraction of work done by A is expressed as

$\frac{1}{x}*combine working rate$

$\frac{1}{x}*\frac{xy}{x+y}\\\frac{y}{x+y} \\$

Hence the fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A is $\frac{y}{x+y} \\$

6 0

3 years ago

Solve for M: 2K − 1 2 = 3 M

LenKa [72]

-2 = KM, just simplify the equation.

5 0

3 years ago