The distance between Branch A and Branch B is given by the Pythagoras theorem
AB² = (Vertical Distance)² + (Horizontal Distance)²
AB² = (4-1)² + (1 - -3)²
AB² = 3² + 4²
AB² = 9 + 16
AB² = 25
AB = 5
BC² = (Vertical distance)² + (Horizontal distance)²
BC² = (-2 - 4)² + (5-1)²
BC² = (-6)² + (4)²
BC² = 36 + 16
BC² = 52
BC = 7.21
Half way of BC = 7.21 ÷ 2 = 3.6 miles
Total distance travelled from A to B and then halfway from B to C is 3.6+5 = 8.6 miles
9+2 = 11 8+3 = 11are you going to do is just add in that's all it does
A. isosceles and acute
hope this helps :)
2(x - 2) + 3(x + 1) = 9
2x - 4 + 3x + 3 = 9 <em>distributed the 2 and 3 on the left side</em>
5x - 1 = 9 <em>added like terms (2x + 3x) and (-4 + 3)</em>
5x = 10 <em>added 1 to both sides</em>
x = 2 <em>divided 5 from both sides</em>
Answer: x = 2