(-7) negative 7 i had some of these questions in pre-algrebra
JD
Simply solve the square.
(X^2-6)^2
3(2x - 1) > = 4(2x - 3) - 3
6x - 3 > = 8x - 12 - 3
6x - 3 > = 8x - 15
6x - 8x > = -15 + 3
-2x > = -12
x < = -12/-2
x < = 6
the incorrect one is : A number line with a closed circle on 6, shading to the right
You mean like in a decimal? It'd be 12.5 or 12.50.... Same thing.