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forsale [732]
3 years ago
12

Owen and Jesse go to a restaurant for breakfast.

Mathematics
2 answers:
alekssr [168]3 years ago
8 0
Part A: D
21,60 x 107% =23,11
Part B: D
23,11 x 115% =26,58
ozzi3 years ago
3 0

Answer: Both of the answers are D

Step-by-step explanation:

21,60 x 107% =23,11

Cost of meal and tax

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Y=x.arctan(x)^1/2. find dy/dx. pls show steps​
Whitepunk [10]

y=x(\arctan x)^{1/2}

Use the product rule first:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dx}{\mathrm dx}(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}

\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}

Use the chain rule to compute the derivative of (\arctan x)^{1/2}. Let z=(\arctan x)^{1/2} and take u=\arctan x, so that by the chain rule

\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm dz}{\mathrm du}=\dfrac{\mathrm du^{1/2}}{\mathrm du}=\dfrac12u^{-1/2}

\dfrac{\mathrm du}{\mathrm dx}=\dfrac{\mathrm d\arctan x}{\mathrm dx}=\dfrac1{1+x^2}

\implies\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}(1+x^2)}

So we have

\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+\dfrac x{2(\arctan x)^{1/2}(1+x^2)}

You can rewrite this a bit by factoring (\arctan x)^{-1/2}, just to make it look neater:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}}\left(2\arctan x+\dfrac x{1+x^2}\right)

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For this case we have the following subtraction:

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Step-by-step explanation:

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