Answer:
w < 8 meters ( w must be greater than 0 because length cannot be 0)
Step-by-step explanation:
One side with building is 23 meters, the other opposite side also will be 23 meters (with rope).
Let width (remaining 2 sides) be "w", he has AT MOST 39 meters of rope, so we can write:
Rope Needed = 23 + 2w < 39
Simplifying:
The range of possible values of w is 
meters (of course w has to be greater than 0)
Answer:
Emilio will have both activities again on the same day after 90 days from this Saturday.
Step-by-step explanation:
<em>To solve this question list the multiples of 30 and 9 to find the first common multiple because the two activities will happen again in </em><em>a number divisible by both 30 and 9.</em>
∵ The multiples of 30 are: 30, 60, 90, 120, ............
∵ The multiples of 9 are: 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, .....
→ The common multiple is 90
∴ The common multiple of 30 and 9 is 90
→ That means the activities will meet again after 90 days from
this Saturday
Emilio will have both activities again on the same day after 90 days from this Saturday.
Answer:
23 %
Step-by-step explanation:
151.34 ÷ 658 × 100
hope this helps
have a nice day <3
Y – y1 = m(x – x1)
y-(-1)=-5(x-2)
Y+1=-5(x-2)
