Answer:
X=5
Step-by-step explanation:
i hope this helps
Answer:
1/20
Step-by-step explanation:
Since there is a 1/4 chance to present on Wednesday, and there is a 1/5 chance to be a presenter out of a group of 5 people,
1/4 * 1/5 = 1/20
Answer: y, z, x
Step-by-step explanation: because the
Answer:
The equation
represents the valid step in solving the given expression ![\sqrt[3]{2x-6}+\sqrt[3]{2x+6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x-6%7D%2B%5Csqrt%5B3%5D%7B2x%2B6%7D)
Therefore the option ![(\sqrt[3]{2x-6})^3=(-\sqrt[3]{2x+6})^3](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B2x-6%7D%29%5E3%3D%28-%5Csqrt%5B3%5D%7B2x%2B6%7D%29%5E3)
Step-by-step explanation:
Given expression is ![\sqrt[3]{2x-6}+\sqrt[3]{2x+6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x-6%7D%2B%5Csqrt%5B3%5D%7B2x%2B6%7D)
To solve the given expression as below :
![\sqrt[3]{2x-6}+\sqrt[3]{2x+6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x-6%7D%2B%5Csqrt%5B3%5D%7B2x%2B6%7D)
![\sqrt[3]{2x-6}=-\sqrt[3]{2x+6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x-6%7D%3D-%5Csqrt%5B3%5D%7B2x%2B6%7D)
cubing on both sides we get
![(\sqrt[3]{2x-6})^3=(-\sqrt[3]{2x+6})^3](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B2x-6%7D%29%5E3%3D%28-%5Csqrt%5B3%5D%7B2x%2B6%7D%29%5E3)
The equation
represents the valid step in solving the given expression ![\sqrt[3]{2x-6}+\sqrt[3]{2x+6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x-6%7D%2B%5Csqrt%5B3%5D%7B2x%2B6%7D)
Therefore the option ![(\sqrt[3]{2x-6})^3=(-\sqrt[3]{2x+6})^3](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B2x-6%7D%29%5E3%3D%28-%5Csqrt%5B3%5D%7B2x%2B6%7D%29%5E3)
Answer:
47.
Step-by-step explanation:
1) the rule:
![f_{avr}=\frac{1}{b-a} \int\limits^b_a {f(x)} \, dx ,](https://tex.z-dn.net/?f=f_%7Bavr%7D%3D%5Cfrac%7B1%7D%7Bb-a%7D%20%5Cint%5Climits%5Eb_a%20%7Bf%28x%29%7D%20%5C%2C%20dx%20%2C)
where a;b are 0 and 12, f(x)=x²-1.
2) according to the rule above:
![f_{avr}=\frac{1}{12-0} \int\limits^{12}_0 {(x^2-1)} \, dx=\frac{1}{12}(\frac{x^3}{3}-x)|^{12}_0=48-1=47.](https://tex.z-dn.net/?f=f_%7Bavr%7D%3D%5Cfrac%7B1%7D%7B12-0%7D%20%5Cint%5Climits%5E%7B12%7D_0%20%7B%28x%5E2-1%29%7D%20%5C%2C%20dx%3D%5Cfrac%7B1%7D%7B12%7D%28%5Cfrac%7Bx%5E3%7D%7B3%7D-x%29%7C%5E%7B12%7D_0%3D48-1%3D47.)