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sveta [45]
4 years ago
7

Solve each quadratic equation. SHOW YOUR WORK. 16. 4x²=100

Mathematics
2 answers:
Romashka-Z-Leto [24]4 years ago
8 0
4x^2 = 100...divide both sides by 4
x^2 = 100/4
x^2 = 25....take the sqrt of both sides, eliminating the ^2
x = sqrt 25
x = 5 <===
jeyben [28]4 years ago
7 0

4x²=100

Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

Divide 4 from both sides

(4x²)/4 = (100)/4

x² = 25

Root both sides to isolate the x

√x² = √25

x = √25

x = 5

5 is your answer

hope this helps

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Last month, Katie started training for the swim team. She swam 20 laps every day for 18 training days. This month, Katie wants t
nasty-shy [4]

She swim 20 laps every day for 18 training days

so total laps done last month = 20*18 = 360 laps

She will swim 3 more laps per training day and add more training days to her monthly schedule.

20 laps + 3 laps = 23 laps

(a)If Katie adds 5 training days to her schedule this month, will she swim 215 more laps?

18 days + 5 days more = 23 days

23 laps every day for 23 training days

so total laps = 23*23 = 529 laps. That is 169 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

If Katie adds 10 more training days to her schedule this month, will she swim 215 more laps?

18 days + 10 days more = 28 days

23 laps every day for 28 training days

so total laps = 23*28 =644 laps. That is 284 more laps than 360 laps done last month. Hence she can swim 215 more laps

(c)If Katie adds 6 more training days to her schedule this month, will she swim 215 more laps?

18 days + 6 days more = 24 days

23 laps every day for 24 training days

so total laps = 23*24 =552 laps. That is 192 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

Build an equation for finding the number of additional training days she needs to swim 215 more laps

Let x be the number of days more

So training days = 18 + x

215 more laps , so total laps = 360 + 215 = 575

3 more laps per training day so 20 + 3 = 23 laps per day

laps * training days = total laps

so equation becomes

23 * (18+x) = 575

Now solve for x

414 + 23x = 575

Subtract 414 from both sides

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4 years ago
The length of a rectangle is 11 in. longer than its width. The perimeter of the rectangle is 86 in.
aliina [53]

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emmasim [6.3K]

Answer:

t=\frac{54.1-53}{\frac{1.78}{\sqrt{12}}}=2.14  

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Step-by-step explanation:

Data provided

\bar X=54.1 represent the sample mean in mg per deciliter of cholesterol level

s=1.78 represent the sample standard deviation

n=12 sample size  

\mu_o =53 represent the value that we want to test  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the mean is higher than 53 mg per deciliter, the system of hypothesis would be:  

Null hypothesis:\mu \leq 53  

Alternative hypothesis:\mu > 53  

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t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

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Replacing into the formula we got:

t=\frac{54.1-53}{\frac{1.78}{\sqrt{12}}}=2.14  

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The p value for this case since we have a right tailed test is:

p_v = P(t_{11}>2.14) =0.0278

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