-- Kenny's weight is 6/7 of Melvin's weight.
-- Melvin's weight is 7/7 of Melvin's weight.
-- The ratio of Kenny's weight to Melvin's weight is (6/7) / (7/7) = 6/7 .
Answer:
Step-by-step explanation:

b ----> base of the triangle
h -----> perpendicular height of the triangle
14 out of 24 can be simplified to 7/12 which is 58.3%
Answer:
∠A = ∠B = 80°
Step-by-step explanation:
The angles are corresponding angles where a transversal crosses parallel lines, so are congruent. That means ...
∠A = ∠B
8x -8° = 5x +25° . . . . . substitute the given expressions
3x = 33° . . . . . . . . . . . . add 8°-5x
x = 11° . . . . . . . . . . . . . . divide by 3
Then the angles are ...
8·11° -8° = 80°
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Explanation:
<u>Given</u>:
- The attached figure showing circle O, chord BC, central angle BOC and inscribed angle BAC
- angle BAC = α + β
<u>Prove</u>:
<u>Proof</u>:
∠BOA +∠BOC +∠AOC = 360° . . . . . sum of arcs of a circle is 360°
2α +∠BOA = 180°, 2β +∠AOC = 180° . . . . . sum of triangle angles is 180°
∠BOA = 180° -2α, ∠AOC = 180° -2β . . . . solve statement 2 for central angles
(180° -2α) +∠BOC +(180° -2β) = 360° . . . . . substitute into statement 1
∠BOC = 2(α +β) . . . . . add 2α+2β-360° to both sides
∠BOC = 2×∠BAC . . . . . substitute given for α+β; the desired conclusion