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3 years ago

6

Pls help ! simplify

2 answers:

butalik [34]3 years ago

7 0

Answer:

$6^{\frac{1}{20} }$

Step-by-step explanation:

$6^{\frac{1}{4} } /6^{\frac{1}{5} }$

1/4 - 1/5 = 1/20

Ilia_Sergeevich [38]3 years ago

4 0

Answer:

B

Step-by-step explanation:

Sqaure roots can be rewritten as fractions.

The numerator will be rewritten as 6^(1/4)

The denominator will he written as 6^(1/5)

Now u can subtract the power, but u have to find a common denominator so it is now (5/20)-(4/20)

The denominator stays the same so you are left with 1/20 which is still the power over 6

6^1/20

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If a=2i+4j, b=2i-5j.What is the vector equation of line AB?.

yan [13]

Answer:

9j

Step-by-step explanation:

vector AB means going to B from A.

= pos. final - pos. initial

= pos.B - pos.A

= (2i + 4j) - (2i - 5j)

= 2i + 4j - 2i + 5j

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8 0

3 years ago

Write a proof for the conjecture using the contrapositive. <br> If 5x + 7 = -13, then x = -4.

KonstantinChe [14]

Answer:

ans x=4

Step-by-step explanation:

5x + 7 = -13
5x = -13 -7
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x = -20/5
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so the answer is x= -4

3 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

Solve ASAP, giving 20+ points

olganol [36]

B.) y = 30x + 55
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3 years ago

What is the standard deviation for 9, 8, 1, 11, 1, 12, 9, 12, 4, 12

shtirl [24]

Answer

I can't tell what you're asking but here is all the things

Step-by-step explanation:

Total Numbers: 10

Mean (Average): 7.9

SD: 4.38305

Variance (SD): 19.21111

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Variance(Population SD): 17.29

6 0

3 years ago