All categories

3 years ago

Pls help ! simplify

Mathematics

2 answers:

butalik [34]3 years ago

7 0

Answer:

$6^{\frac{1}{20} }$

Step-by-step explanation:

$6^{\frac{1}{4} } /6^{\frac{1}{5} }$

1/4 - 1/5 = 1/20

Ilia_Sergeevich [38]3 years ago

4 0

Answer:

Step-by-step explanation:

Sqaure roots can be rewritten as fractions.

The numerator will be rewritten as 6^(1/4)

The denominator will he written as 6^(1/5)

Now u can subtract the power, but u have to find a common denominator so it is now (5/20)-(4/20)

The denominator stays the same so you are left with 1/20 which is still the power over 6

6^1/20

You might be interested in

I bought car of 650,000 and sold it for 520,000. Find the lost Percent ?

harkovskaia [24]

Answer:

20%

Step-by-step explanation:

520,000/650,000 = 0.8

Sold for 80% of original price

Lost percent = 100% - 80%

20%

4 0

3 years ago

If m angle KNM = (8x - 5)° and m angle MNJ = (4x - 19)° , find the measure of angle KNM.

Murrr4er [49]

Answer:

131°

Step-by-step explanation:

Since KNJ is a straight line,

∡KNM +∡MNJ= 180° (adj. ∡s on a str. line)

(8x -5)° +(4x -19)°= 180°

Simplify:

12x -24= 180

+24 on both sides:

12x= 180 +24

12x= 204

Divide both sides by 12:

x= 204 ÷12

x= 17

∡KNM

= (8x -5)°

= [8(17) -5]°

= (136 -5)°

= 131°

4 0

3 years ago

What’s the answer, help please !

Stels [109]

4(5x - 2) - 2(9 - 3x)

= 26x - 26

8 0

3 years ago

If you have 6 cars, but there is only room in your driveway for 3 cars, in how many ways can you arrange the cars in your drivew

Svetradugi [14.3K]

If the order does not matter, cars can be arranged in 20 ways

If an order is important, cars can be arranged in 120 ways

The probability that the three newest cars end up parked in the driveway is 0.167

1. If the order does not matter, combination is used

$\left ({n} \atop {r}} \right.)=\frac{n!}{r!(n-r)!}$

Here, n=6 r=3

using formula,we get

$\left ( {{6} \atop {3}} \right)=\frac{6!}{3!3!} =5*4=20$

2. If an order is important, Permutation will be applicable

$^{n}P_{r} = \frac{n!}{(n-r)!} \\$

∴ $^{6} P_{3} =\frac{6!}{3!(6-3)!}=\frac{6!}{3!} =120$

3. the probability that the three newest cars end up parked in the driveway

P= $\frac{No. of possible outcomes for 3 cars}{total possibilities}$

= $\frac{6*4*5}{6!}$

= $\frac{120}{720}$

= $\frac{1}{6}$ ≈ 0.167

Hence, If the order does not matter, cars can be arranged in 20 ways

If an order is important, cars can be arranged in 120 ways

The probability that the three newest cars end up parked in the driveway is 0.167

Learn more about probability here brainly.com/question/6077878

#SPJ4

7 0

2 years ago

A poster is to have an area of 210 in2 with 1 inch margins at the bottom and sides and a 2 inch margin at the top. find the exac

slavikrds [6]

Let

x-------> the length side of the poster

y-------> the width side of the poster

we know that

Area of the poster is equal to

$210=x*y\\\\ y=\frac{210}{x}$ -------> equation $1$

Area of the printed area is equal to

$Aprinted=(x-2)*(y-3)\\ Aprinted=xy-3x-2y+6$ ----> equation $2$

substitute equation $1$ in equation $2$

$Aprinted=[210]-3x-2*[\frac{210}{x}]+6$

using a graph tool

Find the vertex of the graph

The vertex of the graph is the point that represent the value of x for the largest printed area

see the attached figure

the vertex is the point $(11.83,145)$

the largest printed area is $145 in^{2}$

$x=11.83 in$

find the value of y

$y=\frac{210}{x} \\ \\ y=\frac{210}{11.83} \\ \\ y=17.75in$

therefore

the answer is

The dimensions of the poster are $11.83 in x 17.75 in$

8 0

3 years ago

Read 2 more answers