Okay well, if you make a graph, Point A (7,0) and Point B (4,6) are in the top right quadrant. and Point C (1,1) and Point D (5,3) are in the top left, top right, and bottom left quadrant (I'll link a photo of the graph.)
so the lines intersect and make it perpendicular
Answer: B and C
Step-by-step explanation: For A, vertical angles can be complimentary or supplementary. For D, vertical angles can sometimes be acute but not always.
Answer:
Step-by-step explanation:
Suppose the base formula is y = x^2
You want to go two units left.
basically that is y = (x + 2)^2 just the opposite of what you might think it should be.
Where does the base function have a minimum? It's minimum is as x = 0 and y = 0
Where does y = (x + 2)^2 have it's minimum?
(-2,0)
conclusion. The base function has moved 2 units to the left.
Answer:
i need a photo or an equation TvT
Step-by-step explanation:
TvT TvT TvT
Place a point at (0,-5) because that is the y-intercept (the -5 on the vertical line)
Since the slope is negative two which can be re-written as -2/1 (rise/run) you go down two and to the right once or up two and to the left once, it doesn't matter which. Another point can be placed at (1,-7) or (-3,-1), it still doesn't matter which.
Then you can draw a line connecting the two points.
I hope this helps :)
Let me know if you need further explanation
