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2 years ago

1/8(3d-2)=1/4(d+5) can you help me solve this?

Mathematics

2 answers:

mafiozo [28]2 years ago

3 0

3/8d-1/4=1/4d+5/4 That should be right

Alexus [3.1K]2 years ago

3 0

Distribute
(1/8)(3d) + (1/8)(-2)= (1/4)(d) + (1/4)(5)

3/8d+ -1/4= 1/4d+5/4

subtract 1/4d from both sides

1/8d+ -1/4 - 5/4

add 1/4 to both sides

1/8d=3/2

multiply both sides by 8

d=12

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2 years ago

Find the solution using the Quadratic Formula. (show work) 2x + 8x+ 5 = 0 a. 47 ſ6 b. -27 56 c. -2± √3

Nookie1986 [14]

Answer:

The roots of the equation for the given quadratic equation is $-2\pm \frac{\sqrt{6}}{2}$ .

Step-by-step explanation:

Given quadratic equation as :

2 x² + 8 x + 5 = 0

The roots of the quadratic equation ax² + bx + c = 0 as can be find as :

x = $\frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

x = $\frac{-8\pm \sqrt{8^{2}-4\times 2\times 5}}{2\times 2}$

or, x = $\frac{-8\pm \sqrt{64-40}}{4}$

Or, x = $\frac{-8\pm \sqrt{24}}{4}$

Or, x = $\frac{-8\pm 2\sqrt{6}}{4}$

∴ x = $-2\pm \frac{\sqrt{6}}{2}$

Hence The roots of the equation for the given quadratic equation is $-2\pm \frac{\sqrt{6}}{2}$ . Answer

8 0

3 years ago

PLZZ HELP

9966 [12]

An arithmetic sequence would have a common difference between successive terms, not the case here.

A geometric sequence has a common ratio; let's check:

$\dfrac{1/2}{1/6} = 3$

$\dfrac{3/2}{1/2} = 3$

$\dfrac{9/2}{3/2} = 3$

That's a common ratio of 3 so as far as we can tell a geometric sequence.

Answer: geometric

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3 years ago

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3 years ago

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Part C: the rate of change is 0.

Step-by-step explanation:

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3 years ago