Y=-1/2x+3 is the slope intercept form.
Answer:
search it up its there
Step-by-step explanation:
Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C
A linear equation is a straight line. The equation is of the type y = MX + N
The soluction of that system is Ax^2 + Bx + C = MX + N
=> Ax^2 + (B-M)x + (C-N) = 0
That is a quadratic equation.
A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.
So you must select 0, 1 and 2.
You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.
You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.
Given:
The sides of a right triangle are 2 cm, 3 cm, and 3.6 cm.
To find:
The area of the right triangle.
Solution:
Area of a triangle is:
In the given triangle 3.6 cm is the largest side, it means 3.6 cm is the length of the hypotenuse. So, 2 cm and 3 cm and the base and height of the triangle.
Now, the area of the given triangle is:
Therefore, the area of the given triangle is 3 square cm.
