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Mama L [17]
3 years ago
15

How do you write y=25x-56 in standard form?

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0
To put a slope-intercept into standard form, you have to first cancel out the fractions. So:
y = \frac{2}{5}x - \frac{5}{6}

Turns into:
(5)(6)y = (\frac{2}{5}x - \frac{5}{6})(5)(6)

Simplify:
30y =  (\frac{2}{5}x - \frac{5}{6})(30)

Distribute:
30y = 12x- 25

Since you want to get x and y on the same side, you subtract 12x from both sides to get:
-12x+30y = -25

So, your answer is C. Hope this all made sense! If it doesn't you know where to get a hold of me, so just dm me. Or if you more problems.
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Step-by-step explanation:

\frac{n}{2} +10=2n-4

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Fiesta28 [93]

Step-by-step explanation:

The slope of the given line is -3. Since perpendicular lines have slopes that are negative reciprocals of each other, the slope of the line we need to find is 1/3.

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Read 2 more answers
What are RQS and TQS?
yaroslaw [1]

Answer:

m∠RQS = 72°

m∠TQS = 83°

Step-by-step explanation:

m∠RQS +m ∠TQS = m∠RQT

The two angles combine to make a larger angle

So

m∠RQS = (4x - 20)

m∠TQS = (3x + 14)

(4x - 20) + (3x + 14) = 155

Group the Xs and the constants

4x + 3x - 20 + 14 = 155

Combine like terms

7x - 6 = 155

Add 6 to both sides

7x = 161

Divide by 7 on both sides

x = 23

Check:

4(23) - 20 + 3(23) + 14 = 155

92 - 20 + 69 + 14 = 155

155 = 155

But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.

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Checking:

72 + 83 = 155

8 0
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