Answer:
Defining relations for tangent, cotangent, secant, and cosecant in terms of sine and cosine
Step-by-step explanation:
<h2>HOPE THIS HELPS IM SINGLE 13 STRAIGHT AND IMMA GIRL ;)</h2>
Answer:
Circle
Step-by-step explanation:
Answer: oh kayy
Step-by-step explanation:
Answer/Step-by-step explanation:
Area of a rectangle = Length × Width
Width of the large rectangle = a
Length of the large rectangle = (2 + 3 + 4)
Therefore:
Area of the large rectangle = a(2 + 3 + 4)
Answer: y = 6 mi. .
______________________________________________
Explanation:
______________________________________________
Area of a triangle = (½) * (base) * (height) ;
or, A = (½) * b * h ; or, A = b*h / 2 ;
_____________________________________
Given: A = 24.3 mi ² ;
b = 8.1 mi
___________________
Find the height, "h" ; (in units of "miles", or , "mi" ).
__________________________
Plug in the known values into the formula:
24.3 mi ² = (½) * (8.1 mi) *(h) ;
_____________________________
Solve for "h" (height) ;
_____________________________
(½) * (8.1 mi) = 4.05 mi ;
______________________________
Rewrite:
____________________________
24.3 mi² = (4.05 mi) *(h) ; Solve for "h" ;
_________________________________________
Divide each side of the equation by "(4.05 mi)" ; to isolate "h" on one side of the equation ; and to solve for "h" ;
__________________________________________
24.3 mi² / 4.05 mi = (4.05 mi) *(h) / 4.05 mi ;
→ 6 mi = h ; ↔ h = 6 mi.
→ h = y = 6 mi.
____________________________________________
