The greatest 3 digit number divisible by the 8, the 10, and the 12 is 960. The simplest way of finding the number is to multiply all the divisible factor which is the 8, the 10, and the 12 that results in 960 (8*10*12). If this multiply operation results in more than 3 digit number, therefore we must analyze the factor of the result and eliminate it.
The Answer to question is 2.05
Answer:
208
Step-by-step explanation:
{ed}-{3cb}+{4ba}-{2ea} = {(-15)*(-6)} - {3*5*(-2)} + {4*(-2)*4} - {2*(-15)*4}
={90} - {15*(-2)} + {16*(-2)} - {8*(-15)}
= {90} - {-30} + {-32} - {-120}
= 90 (--)30 (+-) 32 (--) 120
= 90 + 30 - 32 + 120
= 120 - 32 + 120
= 88 + 120
= 208
Answer:
A. None
Step-by-step explanation:
They are no horizontal asymptotes. I get helped from another website when comes to graphs and looking for asymptotes. Good luck on your exam!