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Anton [14]
3 years ago
15

(sinA÷secA)÷(cosA÷sinA) =tan A​

Mathematics
1 answer:
Sloan [31]3 years ago
4 0

(Sin A/ secA) × ( sec A / cos A) = Sin A / cos A = tan A

Question should be cos A ÷ sec A

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How many solutions does this equation have?
kozerog [31]

Hello from MrBillDoesMath!


Answer: infinite solutions


Discussion: I did a double take on this one but  the left hand is

a + 3 + 2a =  3a +3

and the right hand side is

-1 + 3a + 4 = 3a + (4-1) = 3a + 3


The left and right sides of the equation are identical for all "a", i.e. for infinitely many "a" values.


Regards, MrB.







5 0
3 years ago
Read 2 more answers
Find the area of the regular polygon below and round your answer to the nearest tenth.
stira [4]
The 9-sided polygon will have a central angle between the vertex and the center of one side of 360°/(2*9) = 20°. Then the apothem is
  a = (6 in/2)*cot(20°) ≈ 8.242432 in
The perimeter is 9*6 in = 54 in, so the area is
  A = (1/2)Pa = (1/2)*(54 in)*(8.242432 in) ≈ 222.5 in²
4 0
3 years ago
How do you write 4x+y=15 in function form?
sleet_krkn [62]

Answer:

if you mean y-mx+b form

Step-by-step explanation:

y =− 4 x+15

3 0
3 years ago
9)
garri49 [273]

Answer:

tetrahedral

Step-by-step explanation:

According to the valence shell electron pair repulsion theory (VSEPR) the shape of a molecule is dependent on the number of electron pairs on the valence shell of the central atom in the molecule.

The predicted electron pair geometry may sometimes differ from the molecular geometry due to the presence of lone pairs and multiple bonds.

If we consider each nitrogen atom in N2 independently, we will notice that each nitrogen atom has four regions of electron density. Hence the electron pair geometry is tetrahedral.

3 0
3 years ago
An expression is shown below:
Alex73 [517]

Given:

The given expression is:

6x^2y-3xy-24xy^2+12y^2

To find:

Part A: The expression by factoring out the greatest common factor.

Part B: Factor the entire expression completely.

Solution:

Part A:

We have,

6x^2y-3xy-24xy^2+12y^2

Taking out the highest common factor 3y, we get

=3y(2x^2-x-8xy+4y)

Therefore, the required expression is 3y(2x^2-x-8xy+4y).

Part B:

From part A, we have,

3y(2x^2-x-8xy+4y)

By grouping method, we get

=3y(x(2x-1)-4y(2x-1))

=3y(x-4y)(2x-1)

Therefore, the required factored form of the given expression is 3y(x-4y)(2x-1).

3 0
3 years ago
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