Answer:
A.
Step-by-step explanation:
The graph of the y-axis would be x=0
Take two points from both functions. You
will find out that both slopes are the same.
Also you can see that the functions have different y-intercepts.
If the functions have the same slope but different y-intercepts they are parallel to each other
I hope this helps
Answer:
D
Step-by-step explanation:
This is factor by grouping. In factor by grouping, write a quadratic trinomil as 4 terms and group by parenthesis. Then factor by GCF in each pair. If the two parenthesis match, the factoring has worked and the factors will be the GCFs as one and the parenthesis as one other.
The factors here are the GCFs 
and -3 as 
and the parenthesis (x-5).
You subtract the intial from the final. your answer is0.94grams
We begin with an unknown initial investment value, which we will call P. This value is what we are solving for.
The amount in the account on January 1st, 2015 before Carol withdraws $1000 is found by the compound interest formula A = P(1+r/n)^(nt) ; where A is the amount in the account after interest, r is the interest rate, t is time (in years), and n is the number of compounding periods per year.
In this problem, the interest compounds annually, so we can simplify the formula to A = P(1+r)^t. We can plug in our values for r and t. r is equal to .025, because that is equal to 2.5%. t is equal to one, so we can just write A = P(1.025).
We then must withdraw 1000 from this amount, and allow it to gain interest for one more year.
The principle in the account at the beginning of 2015 after the withdrawal is equal to 1.025P - 1000. We can plug this into the compound interest formula again, as well as the amount in the account at the beginning of 2016.
23,517.6 = (1.025P - 1000)(1 + .025)^1
23,517.6 = (1.025P - 1000)(1.025)
Divide both sides by 1.025
22,944 = (1.025P - 1000)
Add 1000 to both sides
23,944 = 1.025P
Divide both by 1.025 for the answer
$22,384.39 = P. We now have the value of the initial investment.
