<h3>
Answer: 40b - 16</h3>
Work Shown:
4(10b-4)
4*10b - 4*4
40b - 16
I multiplied the outer term 4 by each term inside. Refer to the distribution property (aka distributive property).
We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
Answer:
The answer to your question is 14° and 76°
Step-by-step explanation:
Data
leg 1 = x
leg 2 = x/4
angle 1 = ?
angle 2 = ?
Process
To solve problem use trigonometric functions. We must use the trigonometric function that relates both legs (tangent).
tangent Ф = Opposite side / Adjacent side
-Substitution
tan Ф = (x/4) / x
-Simplification
tan Ф = x / 4x
tan Ф = 1/4
- Find Ф
Ф = tan⁻¹(1/4) = 14°
- Find the other acute angle
The sum of the internal angles in a triangles equals 180°
Ф + Ф₁ + 90° = 180
-Solve for Ф₁
Ф₁ = 180 - 90 - 14
-Result
Ф₁ = 76°
Step-by-step explanation:
option C
hope it helps
thank you
