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zhannawk [14.2K]
3 years ago
12

Please help asap! Add using the number line.

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Answer:

0.6

Step-by-step explanation:

1) 1.4-0.8 (A negative and a positive equals a negative, then you just subtract. On the number line you would start at 1.4 and go back)

hope this helps!

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8-7-6-5-4-3-2-1-0-1-2-3
Sindrei [870]

Answer:

-4-5-6-7-8

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which graph shows the equation c = 10+ 3t, where c is the total cost of going to the carnival and t is the number of $3 tickets
lubasha [3.4K]

we have

c = 10+ 3t

where

c---------> is the total cost of going to the carnival

t---------> is the number of \$3 tickets purchased

we know that

<u>the domain of the function is the interva</u>l---------------> [0,∞)

Because the number of tickets can not be negative

<u>The range of the function is the interval</u>-------------> [10,∞)

Because the total cost can not be negative

using a graph tool

see the attached figure

The answer in the attached figure

7 0
3 years ago
Read 2 more answers
Ginny is studying a population of frogs. She determines that the population is decreasing at an average rate of 3% per year. Whe
Rama09 [41]

You can see how this works by thinking through what's going on.

 

In the first year the population declines by 3%.  So the population at the end of the first year is the starting population (1200) minus the decline: 1200 minus 3% of 1200.  3% of 1200 is the same as .03 * 1200.  So the population at the end of the first year is 1200 - .03 * 1200.  That can be written as 1200 * (1 - .03), or 1200 * 0.97

 

What about the second year?  The population starts at 1200 * 0.97.  It declines by 3% again.  But 3% of what???  The decline is based on the population at the beginning of the year, NOT based no the original population.  So the decline in the second year is 0.03 * (1200 * 0.97).  And just as in the first year, the population at the end of the second year is the population at the beginning of the second year minus the decline in the second year.  So that's 1200 * 0.97 - 0.03 * (1200 * 0.97), which is equal to 1200 * 0.97 (1 - 0.03) = 1200 * 0.97 * 0.97 = 1200 * 0.972.

 

So there's a pattern.  If you worked out the third year, you'd see that the population ends up as 1200 * 0.973, and it would keep going like that.

 

So the population after x years is 1200 * 0.97x

5 0
3 years ago
B-c,when b=8 and c=7
elixir [45]
If I understand your question correctly then it's simple all you have to do is use the numbers in the place of the b and c so the question would be what is 8-7 which equals 1 
8 0
3 years ago
1. (01.02)
Anton [14]

Answer:4

Step-by-step explanation:

f(1)=6(1)+2

=8

g(f(1))=2(8)+4/5

=20/5

=4

6 0
2 years ago
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