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3 years ago

Match each description with its symbolic representation.

Mathematics

2 answers:

Mkey [24]3 years ago

4 0

Answer:

The matches are given below.

Step-by-step explanation:

we have to match each description with its symbolic representation.

1. P(A) → c.)The probability that event A occurs.

2. P (A ∩ B) → a.)The probability that both event A and event B occur.

3. P (A ∪ B) → d.) The probability that either event A or event B occurs

4. 1 - P (A ∩ B) → e. The probability that both events A and B do not occur together, but either may occur by itself

5. 1 - P (A ∪ B) → f. The probability that neither event A or event B occurs

6. P (A | B) → b.The probability that event A occurs given the fact that event B occurs

lys-0071 [83]3 years ago

3 0

1. P(A) c. The probability that event A occurs.
2. P (A ∩ B) a.The probability that both event A and event B occur.
3. P (A ∪ B) d. The probability that either event A or event B occurs
4. 1 - P (A ∩ B) e. The probability that both events A and B do not occur together, but either may occur by itself
5. 1 - P (A ∪ B) f. The probability that neither event A or event B occurs
6. P (A | B) b.The probability that event A occurs given the fact that event B occurs

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The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

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61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$

Therefore, the largest angle of the field is 149⁰.

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An arrangement of flowers originally priced at $48.00 is marked down to $39.00. What is the percent of decrease, rounded to the

Mashcka [7]

The answer is C

So how?

I multiplied 48*.19= 9.12 then subtracted that from 48 and got 38.88 which rounds to 39

C is the answer

I hope this helps! :D

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