Answer:
PΔJKL=66
Step-by-step explanation:
so we are given the line segments JK, KL, and LJ which are tangent to k(O), and also that JA=9, AL=10, and CK=14
JL=JA+AL (parts whole postulate)
JL=9+10=19 (substitution, algebra)
JA=JB=9 (tangent segments from the same point are congruent)
CK=KB=14 (tangent segments from the same point are congruent)
JK=JB+KB (parts whole postulate)
JK=9+14=23 (substitution, algebra)
LA=LC=10 (tangent segments from the same point are congruent)
LK=LC+CK (parts whole postulate)
LK=10+14=24 (substitution, algebra)
Perimeter of ΔJKL=LK+KL+LJ (perimeter formula for triangles)
Perimeter of ΔJKL=23+24+19=66 (substitution, algebra)
Pat attention to the ending of the numbers. If there are an odd amount of odds, it's going to be odd. If there is an even amount of odds, it's going to be even. If there's only evens, it's only going to stay even.
Answer:
Line Plot
Step-by-step explanation:
I just toke the assignment! :/
F(1)=-10
f(x), so x=1
f(x)=-10, y=f(x), and y=-10
(x,y)=(1,-10)
0.824.....Apex if answer changed not my fault but kinda helpful
