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CaHeK987 [17]
3 years ago
7

How can you tell whether the parabola had a reflection?

Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0
When it doesn’t look like a U anymore and is upside down
Looking at an equation than when x is negative
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-2(x+1)+6x&lt;-14<br>I need help​
jeka57 [31]

Answer:

x<-3

Step-by-step explanation:

-2(x+1)+6x<-14

Distribute

-2x-2 + 6x < -14

Combine like terms

4x -2 < -14

Add 2 to each side

4x-2+2 < -14+2

4x < -12

Divide by 4

4x/4 < -12/4

x<-3

3 0
3 years ago
State the slope and y-intercept of the graph of y + 2x = 3.
insens350 [35]

Answer:

y-intercept=(0, 3)  slope=-2

hope this help

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What are the domain and range of the function f(x)=(√x-7)+9?
Yanka [14]

Answer:

the domain of the function f(x) is x\ge 7

the range of the function f(x) is f(x)\ge 9

Step-by-step explanation:

Consider the parent function y=\sqrt{x}.

The domain og this function is x\ge 0, the range of this function is y\ge 0.

The function f(x)=\sqrt{x-7}+9 is translated function y=\sqrt{x} 7 units to the right and 9 units up, so

the domain of the function f(x) is x\ge 7

the range of the function f(x) is f(x)\ge 9

3 0
3 years ago
Find the perimeter of a rectangle with a length of 6x+3 and a width of -2x-5.
blsea [12.9K]
The simple way of calculating a perimeter is to add all of the sides.
For a rectangle this would equal 2 x length + 2 x width
P = 2(6x + 3) + 2(-2x - 5)
= 12x + 6 - 4x - 10
= 8x - 4

At a higher level both the length and width must be greater than zero (= zero is a trivial rectangle)
6x + 3 > 0
6x > -3
x > -0.5

-2x - 5 > 0
2x + 5 < 0 (multiplying by -1 reverses the inequality)
2x < -5
x < -2.5

This rectangle cannot exist as x cannot be < -2.5 and > -0.5 at the same time!
8 0
3 years ago
Read 2 more answers
What is the opposite of 3.75 on a number line?​
vodomira [7]

Answer:

-3.75

Step-by-step explanation:

the opposite changes the sign from positive to negative, so the opposite of 3.75 would be -3.75

5 0
3 years ago
Read 2 more answers
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