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irakobra [83]
3 years ago
9

Right answer gets brainlist

Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

Answer:

7

Step-by-step explanation:

Volume

= 1/3 π1^2  7

=1/3*π*1^2*7

umka21 [38]3 years ago
7 0

Answer:

it might be 19.32

Step-by-step explanation:

V = π ∙ r2 ∙ h / 3

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Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp
Sedaia [141]

It looks like you're given

<em>F'(x)</em> = 3<em>x</em>² + 7

and

<em>F</em> (0) = 5

and you're asked to find <em>F(b)</em> for the values of <em>b</em> in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, <em>F</em> (0) = 5.

For the remaining <em>b</em>, you can solve for <em>F(x)</em> exactly by using the fundamental theorem of calculus:

F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt

F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt

F(x)=5+(t^3+7t)\bigg|_0^x

F(x)=5+x^3+7x

Then <em>F</em> (0.1) = 5.701, <em>F</em> (0.2) = 6.408, <em>F</em> (0.5) = 8.625, and <em>F</em> (2.0) = 27.

On the other hand, if you're expected to <em>approximate</em> <em>F</em> at the given <em>b</em>, you can use the linear approximation to <em>F(x)</em> around <em>x</em> = 0, which is

<em>F(x)</em> ≈ <em>L(x)</em> = <em>F</em> (0) + <em>F'</em> (0) (<em>x</em> - 0) = 5 + 7<em>x</em>

Then <em>F</em> (0) = 5, <em>F</em> (0.1) ≈ 5.7, <em>F</em> (0.2) ≈ 6.4, <em>F</em> (0.5) ≈ 8.5, and <em>F</em> (2.0) ≈ 19. Notice how the error gets larger the further away <em>b </em>gets from 0.

A <em>better</em> numerical method would be Euler's method. Given <em>F'(x)</em>, we iteratively use the linear approximation at successive points to get closer approximations to the actual values of <em>F(x)</em>.

Let <em>y(x)</em> = <em>F(x)</em>. Starting with <em>x</em>₀ = 0 and <em>y</em>₀ = <em>F(x</em>₀<em>)</em> = 5, we have

<em>x</em>₁ = <em>x</em>₀ + 0.1 = 0.1

<em>y</em>₁ = <em>y</em>₀ + <em>F'(x</em>₀<em>)</em> (<em>x</em>₁ - <em>x</em>₀) = 5 + 7 (0.1 - 0)   →   <em>F</em> (0.1) ≈ 5.7

<em>x</em>₂ = <em>x</em>₁ + 0.1 = 0.2

<em>y</em>₂ = <em>y</em>₁ + <em>F'(x</em>₁<em>)</em> (<em>x</em>₂ - <em>x</em>₁) = 5.7 + 7.03 (0.2 - 0.1)   →   <em>F</em> (0.2) ≈ 6.403

<em>x</em>₃ = <em>x</em>₂ + 0.3 = 0.5

<em>y</em>₃ = <em>y</em>₂ + <em>F'(x</em>₂<em>)</em> (<em>x</em>₃ - <em>x</em>₂) = 6.403 + 7.12 (0.5 - 0.2)   →   <em>F</em> (0.5) ≈ 8.539

<em>x</em>₄ = <em>x</em>₃ + 1.5 = 2.0

<em>y</em>₄ = <em>y</em>₃ + <em>F'(x</em>₃<em>)</em> (<em>x</em>₄ - <em>x</em>₃) = 8.539 + 7.75 (2.0 - 0.5)   →   <em>F</em> (2.0) ≈ 20.164

4 0
3 years ago
A model of a famous statue is 2 1/2 inches tall. The actual statue is 3 1/3 feet tall. What is the ratio of the height of the mo
Gekata [30.6K]

1. A model of a famous statue is 2\dfrac{1}{2} inches tall that is

\dfrac{2\cdot 2+1}{2}=\dfrac{5}{2} in.

2. The actual statue is 3\dfrac{1}{3} feet tall that is

\dfrac{3\cdot 3+1}{3}=\dfrac{10}{3}\ ft=\dfrac{10}{3}\cdot 12=40\ in.

3. The ratio of the height of the model to the height of the actual statue in simplest form is

\dfrac{\dfrac{5}{2}}{40}=\dfrac{5}{2}\cdot \dfrac{1}{40}=\dfrac{1}{16}.

Answer: \dfrac{1}{16}.

4 0
3 years ago
Pls<br> Help me <br> I need it
ad-work [718]

Answer:

{2}^{7}

Step-by-step explanation:

{2}^{7}  = 128

{7}^{2}  = 49

So,

128 > 49 \\  {2}^{7}  \:  \:  \:  \:    >  {7}^{2}

Therefore 2^7 is greater

4 0
3 years ago
1/2(6N + 8) I need to simplify
Sliva [168]

Answer:

3N + 4

Step-by-step explanation:

The number next to the parenthesis means that you multiply everything inside the parentheses by that number.

1/2(6N+8) = 3N+4

8 0
3 years ago
The percent of working students increased 8.1 to 40.5 what was the present prior to increase
Dmitrij [34]

Answer:

  32.4

Step-by-step explanation:

prior + 8.1 = 40.5 . . . . . . seems to model the problem statement

prior = 32.4 . . . . . . . subtract 8.1 from both sides

Prior to the increase the percent was 32.4.

_____

<em>Comment on the problem statement</em>

When you're talking about a percentage increase in a percentage, it is almost never clear whether you're talking about the percentage of the underlying number, or the percentage of the percentage.

Here, we assume the 8.1 is a percentage of working students, not a percentage of the percentage of workings students. If you actually intend the latter, the percentage before the increase was about 37.465%.

6 0
3 years ago
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