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stepladder [879]
3 years ago
9

If an image of a triangle is congruent to the pre image then the scale factor of the dilation must be n=

Mathematics
2 answers:
Kazeer [188]3 years ago
5 0
1. the image is multiplied by the scale factor. if the scale factor is 2, the image is twice the size of the preimage. if the scale factor is ⅓, the image is one third the size. only a scale factor of 1 preserves congruency
irakobra [83]3 years ago
5 0

Answer: If an image of a triangle is congruent to the pre-image, then the scale factor of the dilation must be n = <u> 1</u>.

Step-by-step explanation:

  • A dilation is a transformation that produces an image that is similar as the original, but has a different size. In a dilation, the corresponding the sides of the pre-image and sides of the image are proportional.

\Rightarrow\frac{\text{pre-image}}{\text{image}}=n (\text{scale factor})

Let ΔPQR is dilated to ΔP'Q'R' such that ΔPQR≅ΔP'Q'R'

By CPCTC, PQ=P'Q'  QR≅Q'R' and PR≅P'R'.

\Rightarrow\frac{PQ}{P'Q'}=\frac{QR}{Q'R'}=\frac{PR}{P'R'}=1

⇒ n=1

Hence, If an image of a triangle is congruent to the pre-image, then the scale factor of the dilation must be n =  1.

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[30 POINTS] Please help!!!
Len [333]

Answer:

Part 1) y=1.5x+5  

Part 2) y=-(2/3)x-(11/3)

Part 3) y=0.25x+2.75    

Part 4) y=-2x+5  

Part 5) y=0.5x-1  

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

m=3/2=1.5

point(-2,2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-2=1.5(x+2)

y=1.5x+3+2

y=1.5x+5

Part 2) we know that  

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

m1*m2=-1

the slope of the line 1 is equal to

m1=1.5

Find the slope m2

1.5*m2=-1

m2=-2/3

Find the equation of the line 2  

we have

m2=-2/3

point(-7,1)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-1=(-2/3)(x+7)

y=-(2/3)x-(14/3)+1

y=-(2/3)x-(11/3)

Part 3) we have

m=1/4=0.25

point(1,3)  

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-3=0.25(x-1)

y=0.25x-0.25+3

y=0.25x+2.75

Part 4) we have

m=-2

b=5 -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

y=mx+b

substitute the values

y=-2x+5

Part 5) we have that

The slope of the line 4 is equal to -2

so

the slope of the line perpendicular to the line 4 is equal to

-2*m=-1\\m=(1/2)=0.5

therefore

in this problem we have

m=0.5

point(-2,-2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y+2=0.5(x+2)

y=0.5x+1-2

y=0.5x-1

Part 6)

using a graphing tool

see the attached figure

3 0
3 years ago
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