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2 years ago

What do we want you to do when we asked you to “solve for x?”

Mathematics

2 answers:

Yuki888 [10]2 years ago

8 0

Answer:

you have to figure out the number for X because X could be any number

Step-by-step explanation:

shepuryov [24]2 years ago

7 0

Answer:

make X as the subject. Since it says solve, so you just simply find what is X. calculate the equation or whatever you are given carefully. read the question repeatedly if you can.

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Solve for x. -3(x+n)=x

marusya05 [52]

Answer:

x = 3/4 n

Step-by-step explanation:

-3(x+n)=x

Distribute

-3x-3n = x

Add 3x to each side

-3x-3n+3x= x+3x

3n = 4x

Divide by 4

3/4n = 3x/3

3/4 n = x

3 0

2 years ago

What is the right answer

Airida [17]

Answer:

{y≥1

,{y-x>0

Step-by-step explanation:

First of all you have to consider the shaded region. It is bound by two lines.

The first line is a solid line that cuts the y-axis at +1. it's equation is y = 1. since the shade region is on the upper side where y values increase, the unequivocally will be y≥1. notice that the sign ≥ is due to the solid line which indicates points on the solid line are part of the solution.

the second line is the broken line. it passes through the origin (0,0) and (1,1) any two points can be taken. the gradient is 1. m= (y1-y2)/(x1-x2) = (0-1)/(0-1)=(-1/-1)= 1. the equation of a straight line is

y=mx + c where m is gradient and c is the VA)ue of y as the line crosses the y axis ( y-intercept) which in this case is 0 at (0,0).so the equation will be y=1(x) + 0

y=x if we subtract x from both sides we have

y-x=0

since the shaded region is on the upper side as y-x increases the in equality will be

y-x>0 notice since the line is broken it shall be just > not≥ because points on a broken line are not included in the shaded region.

8 0

2 years ago

An elevator is 2/3 full. The people in the elevator weigh 1/3 ton altogether. How many tons can the elevator carry when it is co

dimulka [17.4K]

Answer:

Half of a ton

Step-by-step explanation:

2/3 of the elevator are already full and the elevator already weighs 1/3 of ton.The elevator needs 1/3 more of people to make the elevator full so that would be half of 1/3 of a ton which is a sixth.So add 1/6 and 1/3 together ams you get 1/2.

6 0

2 years ago

Which statement about the ordered pairs

myrzilka [38]

(2,-4) is a solution to the equation.

4 0

2 years ago

What is the derivative of 1/square root 4x.

Bumek [7]

Answer:

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Properties

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg]$

Step 2: Differentiate

Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \bigg( \frac{1}{2\sqrt{x}} \bigg)'$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{\sqrt{x}} \bigg)'$
Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{x^\Big{\frac{1}{2}}} \bigg)'$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( x^\bigg{\frac{-1}{2}} \bigg)'$
Derivative Rule [Basic Power Rule]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{-1}{2} x^\bigg{\frac{-3}{2}} \bigg)$
Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4} x^\bigg{\frac{-3}{2}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0

2 years ago